Hello,

Would someone let me know if my math is displayed properly? (like m s x m s = 1) or kg etc. Are they in the right place? I'm not worried about the values. Thank you

Answer: gm = 4.36 m s2 (in 3 sig-figs) Explanation: Knowing the weight of the lander on earth We =36 N and the weight of the same lander on the moon Wu =16 N To find the acceleration due to gravity on the moon, I can use the relationship between weight, mass, and acceleration due to gravity using this formula: weight = mass x acceleration due to gravity. The weight of the lander on earth can be find by the formula: We=muxge Where m represents the mass of the lander, which is constant, and ge gives the acceleration due to Earth's gravity. Since g: =981 ms? So to find the mass of the lander on Earth, m: Wg 9r 36N ~ 981ms? and knowing that 1 N=1kgm s __ 36kgxms 2 ~ 981ms2 =ms?Zxms? = m sC2+(2) =ms =1 _ 36kg " Tos1 =3.67 kg Therefore, the mass of the lander on earth is approximately 3.7 Kg in two significant figures. The mass of the lander remains the same on earth and the moon , only the weight of the lander changes. So, the weight of the lander on the moon can be find using this formula: WM = m x gM Where gm is the acceleration due to gravity on the moon. So, rearranging the above equation to find the acceleration due to gravity on the moon: WM gM = m Adding the values, gm: 16 N 3.67 kg and knowing that 1 N = 1 kg m s-2 16 kg xms-2 3.67 kg = kg x kg = 1 16xms -2 3.67 = 4.35967... m s-2 Therefore, the acceleration of the lander due to gravity on the moon is approximately 4.4 m s-2 in two significant figures