Hello,

Would someone let me know if my math is displayed properly? (like m s x m s = 1) or kg etc. Are they in the right place? I'm not worried about the values. Thank you

Answer: Approximately 250 m s-1 (in 2 sig-figs). Explanation: Speed: = Linear velocity cirumference of orbit = time of orbit 2n(1.8 x 106) 12.5 hrs = 3600 s x 12.5 hrs = 45000 s 2x(1.8 x 106) 45000 s = 251.327 m s-1 ~ 250 m s- (in 2 sig-figs) Therefore, the speed of the satellite is approximately 250 m s-1 in two significant figures