Help?

- 24 - Section 6.3 Inference for a Difference in Proportions Question 5 of 19 0.75 / 1 = Question List X View Policies Show Attempt History Question 1 1/1 Multipart Correct Current Attempt in Progress Your answer is partially correct. Question 2 1/1 Multipart Correct Use the normal distribution to find a confidence interval for a difference in proportions P1 - P2 given the relevant sample results. Assume the results come from random samples. Question 3 1/1 Multipart /Correct A 95% confidence interval for P1 - P2 given that p1 = 0.74 with nj = 550 and p2 = 0.67 with n2 = 350 Give the best estimate for P1 - P2, the margin of error, and the confidence interval. Question 4 1/1 Multipart / Correct Round your answer for the best estimate to two decimal places and round your answers for the margin of error and the confidence interval to three decimal places. Viewing Question 5 0.75 / 1 Best estimate : 0.07 Math Fill in the Partially correct Blank Margin of error : 1.9 Question 6 0.25 / 1 Math Fill in the Confidence interval : Blank Partially correct e Textbook and Media Question 7 1/1 Math Fill in the Hint Assistance Used Correct Blank If we have large samples of sizes nj and n2 from two different groups, we can construct a confidence interval for P1 - P2, the difference in proportions between the two groups, using Question 8 11 Math Fill in the Blank / Correct ( P1 - P2 ) + 2" . 1 P 1 (1 - P1 ) P2 ( 1 - P2) n1 n2 Question 9 0.78 / 1 Multipart O Partially correct where p1 and p2 are the proportions in the respective samples and z" is a standard normal endpoint to give the desired level of confidence. Question 10 1/1 To ensure that the sample size is large enough in each group, we check that nip, 2 10 and n (1 - P1 ) 2 10 and that Multipart Correct n2P2 2 10 and n2 (1 - P2) 2 10. Question 11 0.78 / 1 Attempts: 2 of 4 used Repeat with New Values Multipart Partially correct