Answered step by step
Verified Expert Solution
Question
1 Approved Answer
A 55.0 mL solution of 0.0200 M triethanolamine is extracted with 115 mL of solvent. The distribution constant for the reaction is 4.00 and
A 55.0 mL solution of 0.0200 M triethanolamine is extracted with 115 mL of solvent. The distribution constant for the reaction is 4.00 and the pKa of the protonated form of triethanolamine is 7.762. Calculate the concentration of triethanolamine remaining in the aqueous phase at pH = 6.50 and pH = 8.50. [triethanolamine] at pH = 6.50: M [triethanolamine] at pH = 8.50: M
Step by Step Solution
★★★★★
3.37 Rating (166 Votes )
There are 3 Steps involved in it
Step: 1
Triethanolamin...
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Document Format ( 2 attachments)
63615990bce7c_235664.pdf
180 KBs PDF File
63615990bce7c_235664.docx
120 KBs Word File
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started
Fundamentals of Analytical Chemistry
Authors: Douglas A. Skoog, Donald M. West, F. James Holler, Stanley R. Crouch
9th edition
495558281, 978-0495558286
