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A neutron in a nuclear reactor makes an elastic, head-on collision with the nucleus of a carbon atom initially at rest. (a) What fraction of the neutron's kinetic energy is transferred to the carbon nucleus? (The mass of the carbon nucleus is about 12.0 times the mass of the neutron.) 0.284 (b) The initial kinetic energy of the neutron is 2.30 x 10" J. Find its final kinetic energy and the kinetic energy of the carbon nucleus after the collision. neutron 2.4468 X Enter a number. "differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. J carbon nucleus 6.532 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. JConsider the schematic of the molecule shown, with two hydrogen atoms, H, bonded to an oxygen atom, O. The angle between the two bonds is 1060. If the bond length r = 0.103 nm long, locate the center of mass of the molecule. The mass my of the hydrogen atom is 1.008 u, and the mass mo of the oxygen atom is 15.9999 u. (Use a coordinate system centered in the oxygen atom, with the x-axis to the right and the y-axis upward. Give the coordinates of the center of mass in nm.) 580 H H *CM = 0.00 nm = 15.93 X Use trigonometry to determine the y-coordinate of the hydrogen molecules. Then apply the definition yCM nmA ball of mass m is tossed vertically upwards with an initial speed v . (Use the following as necessary: m, ;, and g.) (a) Find the momentum of the ball when it reaches its maximum height. magnitude P = 0 direction no direction v (b) Find the momentum of the ball when it has reached - its maximum height (for the first time). mvi magnitude D 2 X Use the time-independent kinematic equation to determine the maximum height in terms of v, and g. Then apply your equation for --max, and solve for va the velocity of the ball at 2-max. Finally, use p = my to find the momentum. Because the ball is moving upwards at this point, its momentum is upwards also. direction upwardA small block of mass m, = 0.480 kg is released from rest at the top of a frictionless, curve-shaped wedge of mass my = 3.00 kg, which sits on a frictionless, horizontal surface as shown in Figure a. When the block leaves the wedge, its velocity is measured to be v = 4.80 m/s to the right as shown in Figure b. m] mg a b (a) What is the velocity of the wedge after the block reaches the horizontal surface? 0.480 X There are no external forces acting in the x direction because there is no friction between the block and the horizontal surface. What does this tell you about the x component of the total momentum? m/s to the left (b) What is the height h of the wedge? 2.5 X Will total mechanical energy be conserved during this process? mThe mass of Venus is 4.87 x 10* kg, and the mass of Saturn is 5.68 x 102 kg. The average distance of separation, measured between their centers, is 1.32 x 10 km. (a) Locate the center of mass (in m) of the Venus-Saturn system as measured from the center of Venus. 1.31 x Use the definition of center of mass, with the origin at Venus's center and the x-axis passing through Saturn's center. In this case, mix, = 0. m from Venus's center (b) Is the center of mass of the system located within Venus? (Assume Venus has a radius of 6.05 x 10 m.) Yes O No