Help me solve this math problem

ANSWERS: 1. a. extrema at x = 3, inflection points at x = 0, 2, x intercepts at x = 0, 4, and y intercept at (0, 0) b. extrema at x = -2.528, 0.5275, inflection point at x = -1, x intercepts at x = -3.714, -0.8567, and 1.571, y intercept at (0, -5) c. extrema at X = -0.866, 0, and 0.866, inflection points at x = -0.5, and 0.5, no x intercepts, and y intercept at (0, 0) 2. a. (-oo, 1.3) and ( 0, 1) b. (-1.3, 0) and (1, co) c. -1.5, 1 d. 0 e. -1, 1 3. f' (x ) f" (x) 1.5 1 . 0.5 IN -20 -6 -4 - 2 2 4 6 -6 -7 1 -8 - -10 -1.5 4. An inflection point has the steepest tangent line. 5. Increasing on the interval. 6. 0 7. No, f'(x) doesn't change sign at x = 0. 4 8. - 8 -6 OAN - 8 1 10 9. a. f'(x) = 3x - 5x +1, f" (x) =6x-5 b. X = 0.2324, 1.434 C. X =QUESTIONS: 1. For each polynomial, find the relative extrema, inflection points, x intercepts, y intercept, and graph. a. f(x)=x"4x3 b. f(x)=x3+3x24x5 c. f(x)=2x43x2+5 2. Given the graph of f'(x), find where f(x) is increasing where f(x) is decreasing the relative maximums the relative minimums the inflection points give a possible graph of f(x) nwecve 4. Why is an inflection point a relative extreme of f'(x)? 5. If f'(x)> 0, what does this say about f(x}