help me with this 5 questions

From the given information in each case below, use technology to find the P-value for a chi-square test and give the conclusion for a significance level of a = 0.01. (Use technology to calculate the P-value. Round your answers to five decimal places.) LO USE SALT (a) x2 = 7.8, df = 2 P-value = State the conclusion. O Reject Ho. O Fail to reject Ho. (b) x2 = 12.9, df = 6 p-value = State the conclusion. O Reject Ho. O Fail to reject Ho. (c) x2 = 17.8, df = 9 P-value = State the conclusion. O Reject Ho O Fail to reject Ho. (d) x2 = 21.2, df = 4 P-value = State the conclusion. O Reject Ho. O Fail to reject Ho. (e) x2 = 5.3, df = 3 P-value = State the conclusion. O Reject Ho. O Fail to reject Ho- You may need to use the appropriate table in the appendix to answer this question.A university carried out a study that gives the age distribution for a representative sample of 375 Texas Lottery players. Age Group Frequency from 18 to 24 7 from 25 to 34 33 from 35 to 44 33 from 45 to 54 60 from 55 to 64 101 at least 65 141 Total 375 LO USE SALT Using data from the U.S. Census Bureaut for 2014, the age distribution of adults in Texas was 14% between the age of 18 and 24, 20% between the age of 25 and 34, 19% between the age of 35 and 44, 18% between the age of 45 and 54, 14% between the age of 55 and 64, and 15% aged 65 or older. Is it reasonable to conclude that one or more of the age groups buys a disproportionate share of Texas Lottery tickets? Use a chi-square goodness-of-fit test with a = 0.05. (Hint: See Example 12.2.) Let P1' P2' P3' P4/ Pg and po be the proportions of lottery ticket purchasers in the different age groups. State the null and alternative hypotheses. O Hoi P1 = 14, P2 = 20, P3 = 19, P4 = 18, P5 = 14, P6 = 15 Hai Ho is not true. O Hoip, = 0.14, P2 = 0.2, p3 = 0.19, p4 = 0.18, p5 = 0.14, P6 = 0.15 He: Ho is not true O Ho: P1 = P2 = P3 = P4 = P5 = P6 = 0.17 Hai Ho is not true. O Ho: P1 = P2 = P3 = P4 = P5 = P6 = 17 Hai Ho is not true. O Ho: P1 = 52.5, P2 = 75, P3 = 71.25, p4 = 67.5, p5 = 52.5, P6 = 56.25 Hai Ho is not true. Calculate the test statistic. (Round your answer to two decimal places.) X2 = What is the P-value for this test? (Use technology to calculate the P-value. Round your answer to three decimal places.) P-value = What can you conclude? O Reject Ho. We have convincing evidence that one or more of the age groups buys a disproportionate share of Texas Lottery tickets. O Reject Ho. We do not have convincing evidence that one or more of the age groups buys a disproportionate share of Texas Lottery tickets. O Fail to reject Ho. We do not have con e or more of the age groups buys a disproportionate share of Texas Lottery tickets. O Fail to reject Ho. We have convincing evidence that one or more of the age groups buys a disproportionate share of Texas Lottery tickets. You may need to use the appropriate table in the appendix to answer this question.A particular state university system has five campuses. On each campus, a random sample of students will be selected, and each student will be categorized with respect to political philosophy as liberal, moderate, or conservative. The null hypothesis of interest is that the proportion of students falling in these three categories is the same at all 5 campuses. (a) On how many degrees of freedom will the resulting y test be based? (b) How does the answer in part (a) change if there are 8 campuses rather than 5? (c) How does the answer in part (a) change if there are 6 rather than 3 categories for political philosophy?This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Some colleges now allow students to pay their tuition using a credit card. A report includes data from a survey of 100 public 4-year colleges, 100 private 4-year colleges, and 100 community colleges. The accompanying table gives information on credit card acceptance for each of these samples of colleges. Accepts Credit Does Not Accept Cards for Tuition Credit Cards for Payment Tuition Payment Public 4-Year 84 16 Colleges Private 4-Year 64 36 Colleges Community Colleges 100 0 For purposes of this exercise, suppose that these three samples are representative of the populations of public 4-year colleges, private 4-year colleges, and community colleges in the United States. Is there convincing evidence that the proportions in each of the two credit card categories are not the same for all three types of colleges? Test the relevant hypotheses using a 0.05 significance level. (Hint: See Example 12.5.)Each person in a representative sample of 450 college students age 18 to 24 was classified according to age and to the response to the following question: "How often have you used a credit card to buy items knowing you wouldn't have money to pay the bill when it arrived?" Possible responses were never, rarely, sometimes, or frequently. The responses are summarized in the table. Age 18 to 20 Age 21 to 22 Age 23 to 24 Never 72 62 29 Rarely 37 34 32 Sometimes 34 42 40 Frequently 12 24 32 LA USE SALT Do these data provide evidence that there is an association between age group and the response to the question? Test the relevant hypotheses using a = 0.01. State the appropriate null and alternative hypotheses. Ho: The proportions falling into each of the three age groups are not the same for all four responses to the question. He: The proportions falling into each of the three age groups are the same for all four responses to the question. O Ho: The proportions falling into each of the three age groups are the same for all four responses to the question. H: The proportions falling into each of the three age groups are not the same for all four responses to the question. O Ho: There is tion between age group and t ponse to the question. H: There is no association between age group and the response to the question. O Ho: There is no association between age group and the response to the question. He: There is an association between age group and the response to the question. Find the test statistic and P-value. (Use SALT. Round your test statistic to three decimal places and your P-value to four decimal places.) x2 = P-value = State the conclusion in the problem context. O Fail to reject Ho. There is not convincing evidence that there is an association between age group and the response to the question. O Reject Ho. There is not convincing evidence that there is an association between age group and the response to the question. O Fail to reject Ho. There is convincing evidence that there is an association between age group and the response to the question. O Reject Ho. There is convincing evidence that there is an association between age group and the response to the