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Help me with this 5 questions please!! 1) The Acme Company manufactures widgets. The distribution of widget weights is c) Approximately, what percent of the

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Help me with this 5 questions please!!

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1) The Acme Company manufactures widgets. The distribution of widget weights is c) Approximately, what percent of the scores in a dataset are below bell-shaped. The widget weights have a mean of 52 ounces and a standard deviation the 30th30th percentile? of 8 ounces . Use the Standard Deviation Rule, also known as the Empirical Rule. Consider the following bell-shaped distribution where $2 and 64 are one standard Suggestion: sketch the distribution in order to answer these questions. deviation from the mean each. a) 68% of the widget weights lie between and b) What percentage of the widget weights lie between 36 and 60 ounces? c) What percentage of the widget weights lie below 76? 46 ss 64 70 76 2) The time needed to complete a math examination is bell-shaped with a mean of 90 minutes and a standard deviation of 15 minutes. Determine the Median and Variance of the distribution. a) What percentage of students will complete the exam in 60 minutes or less? % 1. Median = 58 b) Assume that the class has 160 students and that the examination period is 120 minutes in length. How many students do you expect will not be able to complete the exam in the 2. Variance = allotted time ? Round answer to the nearest whole number . c) A student is classified as extremely "efficient" if the amount of time spent on the exam is the lowest 0.15% for the distribution. What is the upper limit for the time it takes an extremely "efficient" student to finish the exam? Use the empirical rule or your knowledge of the normal disdtribution to answer the following. Report answers as integers. minutes 3) Given the following table of unsorted values, calculate the indicated locator and percentile. Do not round your results. 3. The lower limit for the highest 2.5% of the data is approximately = 30 95 82 90 33 41 58 18 4. The upper limit for the lowest 97.5% of the data is approximately = 73 92 68 22 21 43 9 31 67 97 23 50 89 48 60 42 74 71 96 34 24 5. The range of the middle 95% of the data is approximately = 7 65 16 47 45 79 75 83 32 17 72 19 20 38 88 27 29 40 85 The 5-number summary for a data set is as follows: 99 8 86 87 14 70 100 61 91 55 26 5 76 80 -55 -3 20 33 84 77 63 57 81 64 49 11 78 93 28 a. The range of the dataset = LL 94 10 52 59 62 25 53 6 b. The first (lower) quartile = a) Determine the locator for the 30th30th percentile, L30L30. c. The interquartile range, IQRIQR = and it represents the range of the L30L30 - middle % of the data . b) Find the 30th30th percentile, P30P30. d. The 50th50th percentile = P30P30- e. About 75% of the data are greater than f. There are about | % of the data between -3-3 and 20 English (Canada) Accessibility: InvestigateThe Acme Company manufactures widgets. The distribution of widget weights is bell- shaped. The widget weights have a mean of 52 ounces and a standard deviation of 8 ounces. Use the Standard Deviation Rule, also known as the Empirical Rule. Suggestion: sketch the distribution in order to answer these questions. a) 68% of the widget weights lie between 44 and 60 b) What percentage of the widget weights lie between 36 and 60 ounces? c) What percentage of the widget weights lie below 76 ? Question Help; D] VideoThe time needed to complete a math examination is bell-shaped with a mean of 90 minutes and a standard deviation of 15 minutes. a) What percentage of students will complete the exam in 60 minutes or less? b) Assume that the class has 160 students and that the examination period is 120 minutes in length. How many students do you expect will not be able to complete the exam in the allotted time? Round answer to the nearest whole number. c) A student is classified as extremely "efficient" if the amount of time spent on the exam is the lowest 0.15% for the distribution. What is the upper limit for the time it takes an extremely "efficient" student to finish the exam? minutesGiven the following table of unsorted values, calculate the indicated locator and percentile. Do not round your results. 90 m + O Co O 86 100 LO Co 10 LO N a) Determine the locator for the 30th percentile, L30. 30 = (1) b) Find the 30th percentile, P30. P30= 4 c) Approximately, what percent of the scores in a dataset are below the 30th percentile? Priv Terr Question Help: Message instructor

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