help please

6. Freeting Point Depression (35 points). Stearic atid, cooling portion equation: Stearic acid, freeaing portion: y=0.0599x+80.454y=0.002x+67.516 Stearic acid, time 2 tines intersect: Stearic acid, calculated freeting point: Stearic acid and unknown, cooling portion: Stearic acid and unknown, freezing portion: y=0.0612x+75.015y=0.0007x+63.158 Stearic acid and unknown, time 2 linesintersect: Stearic acid and unknown, calculated freezing point: Freezing point depression: Mass of stearic acid: Mass of unknown used: 9.012R0.983B Molality of unknown in solution: Moles of unknown in solution: Molar mass of unknown: Show work: 6 X. Freezing point depression y=mx+b;m= slope of cooling or freezing curve; b=y-intercept of freezing or cooling curve T= (Final temperature) - (Initial Temperature) Ti=Kimsolute Ktof water =1.86C/m Krof stearic acid =4.5C/m mtolute= molality = moles of solute /kg of solvent molar mass of solute =g of solute /mol of solute