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help please A mixture of 1.0 mole of CO2(g) and 1.0 mole of Colg) are contained in a 1000 ml vessel. After a while, at
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A mixture of 1.0 mole of CO2(g) and 1.0 mole of Colg) are contained in a 1000 ml vessel. After a while, at equilibrium there are 2.0 moles of water vapour found in the vessel. The following reversible reaction takes place CO(g) + H20(g) - CO2(g) + H2(g) Keq = 0.64 How many moles of the different molecules will be present after equilibrium is obtained? CO(g) H2O(g) CO2(g) H2(9) 01.0 1.0 2.0 0 C -X +x +x El 1-X 2-X 1+x +x (enter the more negative answer first) The two solutions are x = Therefore the final concentrations of each gas is Gas Moles co 0.58 H2O 1.58 CO 142 H2 0.42Step by Step Solution
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