Question
Help please: c program only The number of ways of arranging r objects chosen from n, where order is important (these are called permutations) is:
Help please: c program only The number of ways of arranging r objects chosen from n, where order is important (these are called permutations) is: perm(r, n) = n! (n r)! Also, the number of ways of choosing r objects from n without regard to order (these are called combinations) is: comb(r, n) = n! (n r)!r! Write three functions, fact(n) (= n!), perm(r, n), comb(r, n) , and a main program to test them. The main prompts the user to enter the values of r and n then prints the values of r, n, perm(r, n) and comb(r, n) to an output file. The function perm must call the function fact. The function comb must call both perm and fact. The input/output should look like: Enter r and n: 3 5 The number of permutations of 3 objects chosen from 5 is 60 The number of combinations of 3 objects chosen from 5 is 10 For marking purposes run your program with r = 5 and n = 9 /* File: permcomb.c
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