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Help solve for A The manager of a warehouse must decide on the number of loading docks to request fo a new facility in order
Help solve for A
The manager of a warehouse must decide on the number of loading docks to request fo a new facility in order to minimize the sum of dock costs and driver-truck costs. | |||||||||||||||||||||||
The manager has learned that each driver-truck combination represents a cost of $600 per day and that each dock plus loading crew represents a cost of $1,000 per day. | |||||||||||||||||||||||
(a) How many docks should be requested if trucks arrive at the rate of three per day, each dock can handle five trucks per day, and both rates are Poisson? Show support to your answer. | 1 | ||||||||||||||||||||||
(b) An employee has proposed adding new equipment that would speed up the loading rate to 5.71 per day. The equipment would cost $100 per day for each dock. | Yes | ||||||||||||||||||||||
Should the manager invest in the new equipment? Show support to your response. | |||||||||||||||||||||||
Copy and paste onto this worksheet the output used in anwering the questions above. | |||||||||||||||||||||||
When copying and pasting, use Copy > Paste Special > Picture | |||||||||||||||||||||||
Hint: For parts (a) and (b), compute the cost of the servers (per day) and the cost associated | |||||||||||||||||||||||
with trucks and drivers in the system per day. | |||||||||||||||||||||||
See Example 6 on page 810 for a similar situation | |||||||||||||||||||||||
Multiple Channel Waiting Line Model | |||||||||||||||||||||||
Arrival rate l = | 3 | Service rate m = | 5 | Multiple Channel Waiting Line Model | |||||||||||||||||||
Increment Dl = | 0.1 | Increment Dm = | 0.1 | Arrival rate l = | 3 | Service rate m = | 5.71 | ||||||||||||||||
Interarrival Time 1/l = | 0.3333 | Service time 1/m = | 0.2000 | Increment Dl = | 0.1 | Increment Dm = | 0.1 | ||||||||||||||||
Interarrival Time 1/l = | 0.3333 | Service time 1/m = | 0.1751 | ||||||||||||||||||||
Number of servers (max 12) | M = | 1 | 2 | 3 | 4 | 5 | 6 | ||||||||||||||||
System Utilization | r = | 0.6000 | 0.3000 | 0.2000 | 0.1500 | 0.1200 | 0.1000 | Number of servers (max 12) | M = | 1 | 2 | 3 | 4 | 5 | 6 | ||||||||
Probability system is empty | P0 = | 0.4000 | 0.5385 | 0.5479 | 0.5487 | 0.5488 | 0.5488 | System Utilization | r = | 0.5254 | 0.2627 | 0.1751 | 0.1313 | 0.1051 | 0.0876 | ||||||||
Probability arrival must wait | Pw = | 0.6000 | 0.1385 | 0.0247 | 0.0035 | 0.0004 | 0.0000 | Probability system is empty | P0 = | 0.4746 | 0.5839 | 0.5908 | 0.5913 | 0.5913 | 0.5913 | ||||||||
Average number in line | Lq = | 0.9000 | 0.0593 | 0.0062 | 0.0006 | 0.0001 | 0.0000 | Probability arrival must wait | Pw = | 0.5254 | 0.1093 | 0.0173 | 0.0022 | 0.0002 | 0.0000 | ||||||||
Average number in system | Ls = | 1.5000 | 0.6593 | 0.6062 | 0.6006 | 0.6001 | 0.6000 | Average number in line | Lq = | 0.5816 | 0.0389 | 0.0037 | 0.0003 | 0.0000 | 0.0000 | ||||||||
Average time in line | Wq = | 0.3000 | 0.0198 | 0.0021 | 0.0002 | 0.0000 | 0.0000 | Average number in system | Ls = | 1.1070 | 0.5643 | 0.5291 | 0.5257 | 0.5254 | 0.5254 | ||||||||
Average time in system | Ws = | 0.5000 | 0.2198 | 0.2021 | 0.2002 | 0.2000 | 0.2000 | Average time in line | Wq = | 0.1939 | 0.0130 | 0.0012 | 0.0001 | 0.0000 | 0.0000 | ||||||||
Average waiting time | Wa = | 0.5000 | 0.1429 | 0.0833 | 0.0588 | 0.0455 | 0.0370 | Average time in system | Ws = | 0.3690 | 0.1881 | 0.1764 | 0.1752 | 0.1751 | 0.1751 | ||||||||
| Average waiting time | Wa = | 0.3690 | 0.1188 | 0.0708 | 0.0504 | 0.0391 | 0.0320 | |||||||||||||||
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