Help with d thank you!

1d kinematics Begin Date: 1/19/2023 8:00:00 PM -- Due Date: 1/2//2023 1 (0%) Problem 9: The acceleration due to gravity on the moon, gM , has one-sixth of the Earth's value, g. A ball is thrown straight up on the Moon, and its total time of flight, meaning the time it takes to return to the Moon's surface, is t = 8.42 s . y V. tus Otheexpertta.com leted leted leted 25% Part (a) What is the numeric value of the magnitude, in meters per squared second, for the acceleration due to gravity on the moon? gM = 1.630 m/s2 Correct! leted 25% Part (b) Enter an expression for the maximum height achieved by the ball on the moon, hm, in terms of the gravitational acceleration on earth, g, leted and the total time of flight, tflight . leted hM = ( (1/6 ) g tfight )/8 Correct! leted 25% Part (c) Given the value of the total time of flight in the problem statement, what is the maximum height, in meters, of the ball on the Moon? hM = 14.475 hM = 14.48 m Correct! 4 25% Part (d) Assuming the same total time of flight, what is the difference between the maximum height of the ball thrown on the Moon, hm, and the maximum height of an identical ball thrown on the Earth, he ? Ignore the effects of the Earth's atmosphere. hM - he = Grade Summary m Deductions 0% Potential 100% sin( cos tanO 7 8 9 HOME Submissions cotan( asin( acos() 4 5 6 Attempts remaining: 10 (0% per attempt atan( acotan( sinh( 2k 1 2 3 detailed view cosho tanh() cofanho END