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Next question The amount of time adults spend watching television is closely monitored by firms because this helps to determine advertising pricing for commercials. Complete parts (a) through (d). x is approximately normal with u- = 2.35 and o; = 0.249162 . (Round to six decimal places as needed.) (c) Determine the probability that a random sample of 60 adults results in a mean time watching television on a weekday of between 2 and 3 hours. The probability is 0.9155 . (Round to four decimal places as needed.) (d) One consequence of the popularity of the Internet is that it is thought to reduce television watching. Suppose that a random sample of 55 individuals who consider themselves to be avid Internet users results in a mean time of 2.01 hours watching television on a weekday. Determine the likelihood of obtaining a sample mean of 2.01 hours or less from a population whose mean is presumed to be 2.35 hours. The likelihood is 0.0957 . (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box within your choice. (Round to the nearest integer as needed.) O A. If 1000 different random samples of size n = 55 individuals from a population whose mean is assumed to be 2.35 hours is obtained, we would expect a sample ten mean of 2.01 or more in about of the samples. Incorr B. If 1000 different random samples of size n = 55 individuals from a population whose mean is assumed to be 2.35 hours is obtained, we would expect a sample mean of 2.01 or less in about |of the samples. O C. If 1000 different random samples of size n = 55 individuals from a population whose mean is assumed to be 2. " hours is obtained, we would expect a sample (/4) cces mean of exactly 2.01 in about of the samples