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Here are 6 celebrities with some of the highest net worths (in millions of dollars) in a recent year: George Lucas (5500), Michael Jordan (1700),

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Here are 6 celebrities with some of the highest net worths (in millions of dollars) in a recent year: George Lucas (5500), Michael Jordan (1700), Paul Mccartney (1200), J. K. Rowling (1000), David Copperfield (1000), and Jerry Seinfeld (950) . Find the range, variance, and standard deviation for the sample data. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? The range is $ million. (Round to the nearest integer as needed.) The variance is million dollars squared. (Round to the nearest integer as needed.) The standard deviation is $ million. (Round to the nearest integer as needed.) What do the results tell us about the population of al celebrities? O A. Because the statistics are calculated from the data, the measures of variation are typical for all celebrities. O B. Because the data are from celebrities with the highest net worths, the measures of variation are not at all typical for all celebrities. O C. Because the statistics are calculated from the data, the measures of variation cannot tell us about other celebrities. O D. Because the data are from celebrities with the highest net worths, the measures of variation are typical for all celebrities. Based on the nature of the amounts, what can be inferred about their precision? so it would make sense to round the results to the nearest Because all of the amounts end with it appears that they are rounded to the nearestIn a Leichtman Research Group survey of 800 TV households, 75.4% of them had at least one Internet-connected TV device (for example, Smart TV, standalone streaming device, connected video game console). A marketing executive wants to convey high penetration of Internet-connected TV devices, so he makes the claim that the percentage of all homes with at least one Internet-connected TV device is equal to 80%. Test that claim using a 0.01 significance level. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Let p denote the population proportion of all homes with at least one Internet-connected TV device. Identify the null and alternative hypotheses. Ho : P H1 : P (Type integers or decimals. Do not round.) Identify the test statistic. Z = (Round to two decimal places as needed.) Identify the P-value. P-value = (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the claim that the percentage of all homes with at least one Internet-connected TV device is equal to the null hypothesis. There sufficient evidence to 80%.Heights (cm) and weights (kg) are measured for 100 randomly selected adult males, and range from heights of 134 to 189 cm and weights of 37 to 150 kg. Let the predictor variable x be the first variable given. The 100 paired measurements yield x = 168.21 cm, y = 81.66 kg, r = 0.152, P-value =0.131, and y = - 106 + 1.13x. Find the best predicted value of y (weight) given an adult male who is 171 cm tall. Use a 0.01 significance level. The best predicted value of y for an adult male who is 171 cm tall is kg. (Round to two decimal places as needed.)

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