Here is the code I made, but the test case is not working, it goes wrong when the binary string convert to decimal. please help.

Note: this is c++ not c

#include "stdafx.h"

#include

#include

#include

#include

using namespace std;

// function for option 1

void decToBin(int number)

{

int array[16];

int i = 0;

for (int counter = 0; counter

{

array[counter] = 0;

}

while (number > 0)

{

array[i] = number % 2;

number = number / 2;

i++;

}

for (int counter = 15; counter >= 0; counter--)

{

cout

}

}

// function for option 2

void binToDec(int number)

{

int array[16];

double dec = 0;

int i = 0;

for (int counter = 0; counter

{

array[counter] = 0;

}

while (number != 0)

{

array[i] = number % 10;

number = number / 10;

i++;

}

for (int counter = 0; counter

{

if (array[counter] != 0)

{

dec += pow(2, counter);

}

}

cout

}

// negative number

void negat(int number)

{

long array[16];

double dec = 0.0;

int length = 16;

int j = 15;

int a = 0;

//store the number in the array check

for (int counter = 15; counter >= 0; counter--)

{

array[counter] = number % 10;

number = number / 10;

}

// flip the numbers check

for (int counter = 15; counter >= 0; counter--)

{

if (array[counter] == 0)

{

array[counter] = 1;

}

else {

array[counter] = 0;

}

}

// add 1

if (array[length] == 1)

{

while (array[length] == 1)

{

array[length] = 0;

length++;

}

array[length + 1]++;

}

else

{

array[15]++;

}

//reverse array

int temp, i;

for (i = 0; i

temp = array[16 - i - 1];

array[16 - i - 1] = array[i];

array[i] = temp;

}

/// to dec

for (int counter = 0; counter

{

if (array[counter] != 0)

{

dec += pow(2, counter);

}

}

dec = 0 - dec;

cout

}

void ShowMenu()

{

cout

cout

cout

}

/**********************************************************/

int main()

{

int number;

string ans;

int choice;

bool Quit = false;

char move = 'z';

while (!Quit) {

ShowMenu();

cout

cin >> move;

switch (move) {

case '1':

int number;

string ans;

cout

cin >> number;

decToBin(number);

break;

case '2':

int number;

string ans;

cout

cin >> number;

if (number / 1000000000000000 == 1) {

negat(number);

}

else {

binToDec(number);

}

break;

case '3': //user wants to quit

Quit = true; //execution continues after the switch

//or do this to end program

//return 0;

break;

default:

cout

break;

}

}

cout

system("pause");

return 0;

}

Part 1- HLL You can use any high-level language you wish for this part (C+t or Java is recommended), but you cannot call built-in library functions to accomplish these tasks automatically. Write a 16-bit binary conversion program that can either convert a 16-bit unsigned decimal to binary or convert a string of 16-bit binary to an unsigned decimal. Use loop and a menu to allow user to make repeated selection as needed. You can assume user will always enter valid input data. You must use a function/method for each conversion: A function/method that receives an unsigned integer (limit to 16 bits) and returns a 16-bit string containing the binary representation of that integer A function/method that receives a string containing a 16-bit unsigned integer and returns an unsigned integer value of that binary value Run the following test cases and confirm that results are correct Unsigned integers 36 and 65535 Binary strings 0000000000111011 and 1111001000000000 Sample input and output: Binary conversion program by [Your Name] This program can handle 16-bit unsigned values Select an option below to perform conversion 1unsigned decimal to binary 2binary to unsigned decimal 3 -quit Enter an option --> 1 Please enter a decimal value-36 Decimal 36 is converted to binary 0000000000100100 Enter an option> 2 Please enter a binary value0000000000111011 Binary 000000000011101 is converted to decimal 59 Enter an option --> 3 Thanks for using my program