Here is the questions :

Number the masses 1-18. If we start on the left side and number to the right.

There are masses which are hanging that pull down with a force due to gravity of F=mg. They either pull the system to the left or the right. Solve for the force of each hanging mass, and give each a direction of either left or right.

step A - Find Fg for masses 8, 9, 14, 17 and18 as they are pulling to the right

step B - Find Fg for masses 1 and 7 as they are pulling to the left.

There are masses which are on ramps. Solve for the Ramp Force using Fr=mgsin, where is the angle of the ramp compared to horizontal. Give these each of these a direction of left or right based on which way they want to slide.

step C - Find Fr for masses 5, 11 and 16 as they are on ramps leaning to the right.

step D - Find Fr for masses 3 and 13 as they are on ramps leaning left

Total all the right forces and all of the left forces. Whichever is bigger, determines the direction the system will slide.

Now calculate the force of friction on flat surfaces using Ff=mg, and the friction on ramps using Ff=mgcos (again ensuring that is the angle the ramp makes to horizontal. Since friction always opposes motion, subtract all of these frictions from the net force from the ramps and hanging masses.

step E - Find Ff on the flat surfaces for masses 2, 4, 6, 10, 12 and 15.

step F - Find Ff on the ramps for masses 3, 5, 11, 13 and16.

Fnet = Fright-Fleft-Ff

Fnet = Fhanging masses pulling right + Framp masses pulling right - Fhanging masses pulling left- Framp masses pulling left - Ffriction of all sliding masses.

or Fnet = Forces in A + Forces in C - Forces in B- Forces in D - All forces of friction

This net force is what causes the acceleration of the whole system, so we can calculate acceleration by using the equation a= Fnet/total mass

step G - Find the total mass of all 18 masses added together.

step H - Solve for The acceleration using acceleration=Fnet/Mass found in G.

Do not worry about the points on the ropes labelled with the letters until you are solving for the tension in the ropes at those points.

I did Tension G using your equation (which is correct) and got a different answer than you did. Please show your substitution so I know what you are putting in for the letters. Did you use 9.8 for g or did you use 9.81? What did you plug in for a? (when I put in 9.8 for g, and used your a of 2.437, and I get 24.474N, then if I use 9.81 for g, I get 24.494N. You got 24.874 somehow. I can not determine what you are doing if you do not show the substitution into equations. You will also lose marks if you do not show this. Show the equation, Show the same equation with all of your values substituted in for the variables, and then show the answer. Also do not forget to put a direction on all of the tensions. They are Forces and Forces are vector quantities and therefore need a direction. An arrow in square brackets is fine or [up], [down], [left], [right], or [up and left] etc. Since you are using word to type your answer up, you could insert arrow symbols in the place of the words I showed above.

C THE BIG Tension Problem Determine the acceleration of the system and the tension at each point. Verify 2 of the tensions. HK = 0.2 ON ALL - MK = 0. 1 ON ALL - AA + 0.15 ON ALL SURFACES SURFACES SURFACES 8kg D 6kg 3 kg 3KS 4 KA 8 kq E 15kg 5kg 4 kq 140" 10kg 4kg 8kg 2K 3kg 8kq 60" 7kg