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Here, we will again discuss that idea, and we will do so by focusing on the percentage of plain green M&Ms that are produced by

Here, we will again discuss that idea, and we will do so by focusing on the percentage of plain green M&Ms that are produced by Mars, Inc. The Mars company claims that 10% of the plain M&M candies they produce are green.

9. Suppose you take a random sample of n = 50 candies from the population of plain M&M candies and you note that 7 of these candies are green. What will your sample proportion, or ?, be? Please calculate this number below, and present your answer to two decimal places.

10. The number you wrote in response to Question 9 describes a sample. We call a number that describes a sample a _________________________.

11. In the population of plain M&M candies, 10% of the candies are green. Written as a proportion, this number would be 0.10, and we use the symbol p to denote a population proportion. We would consider the population proportion to be a __________ because it's a number that describes a population.

Imagine now that 20 of your STAT 1350 classmates each take a random sample of n = 50 plain M&M candies from the population. Each classmate then determines the proportion of green candies in their sample. The graph below?called a dot plot?shows each of these sample proportions. Each proportion appears as a dot above a number line, and the number line gives us different values of our sample proportions. If any dots are stacked in a column, it would mean that more than one student obtained that same sample proportion. For example, there are four dots stacked in a column at 0.08, and this means that four students obtained a sample proportion of 0.08.

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\f20000- 15000 Frequency 10000 ill 5000 0 0.0 0.1 0.2 Sample Proportion pSample size Distribution of Sample Proportions Mean and Standard Deviation n = 50 20000- Mean = 0.10 15000 Standard Deviation = 0.0424 Frequency 10000 5000 0.0 0.1 0.2 Sample Proportion p n = 70 15000 Mean = 0.10 Frequency 10000 Standard Deviation = 0.0358 5000 0.0 0.1 0.2 Sample Proportion p n = 100 15000 Mean = 0.10 10000 Frequency Standard Deviation = 0.0299 5000 0.0 0.1 0.2 Sample Proportion p

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