Hery, first few pictures are there just for reference. Need help with 5, 6, 7 (they are blank in answers). It would be great if I could get some help. I am lost. Thanks

Throughout this experiment the current is measured to be I = 2.667 mA. After being discharged capacitor 1 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 1. Graph data Linear fit for Linear fit for Linear fit for Latest|Potential Latest|Potential Latest|Potential Pote mt + b Pot= mt + b Pot=mt + b m (Slope): 0.9089 V/S m (Slope): 0.9100 V/S m (Slope): 0.9100 V/S b (Y-intercept): -3.243 v b (Y-intercept): -2.143 V b (Y-intercept): -1.901 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.007985 V RMSE: 0.008305 V RMSE: 0.008095 V C1 = 2931 +1.77 Your last answer was interpreted as follows: 2931 Your last answer was interpreted as follows: 1.77 Correct answer, well done. Marks for this submission: 0.22/0.22. Correct answer, well done. Marks for this submission: 0.22/0.22. Accounting for previous tries, this gives 0.15/0.22. After being discharged capacitor 2 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 2. Graph data: Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Potemt + b Pot=mt + b Pot=mt + b m (Slope): 1.973 V/S m (Slope): 1.976 V/S m (Slope): 1.977 V/S b (Y-intercept): -3.684 V b(Y-intercept): -3.330 v b (Y-intercept): -3.051 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.007986 V RMSE: 0.008103 v RMSE: 0.007582 v UF C2 = 1350.15 + 1.367 Your last answer was interpreted as follows: 1350.15 Your last answer was interpreted as follows: 1.367 Correct answer, well done. Marks for this submission: 0.22/022. Correct answer, well done. Marks for this submission: 0.22/0.22. After being discharged capacitor 3 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 3. Graph data Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Pot=mt + b Pot=mt + b Pot=mt + b m (Slope): 4.278 V/s m (Slope): 4.294 V/s m (Slope): 4.295 V/S b(Y-intercept): -9.054 V b (Y-intercept): -6.868 V b (Y-intercept): -8.772 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.01681 V RMSE: 0.005470 V RMSE: 0.007557 v C3 = 621.83 + 1.234 F Your last answer was interpreted as follows: 621.83 Your last answer was interpreted as follows: 1.234 Correct answer, well done. Marks for this submission: 0.22/0.22. Correct answer, well done. Marks for this submission: 0.22/0.22. A parallel circuit Use the values you calculated above to predict the capacitance of C and Cs connected in parallel with an uncertainty. C2,3 AF 1988.81 2.601 Your last answer was interpreted as follows: 1988.81 Your last answer was interpreted as follows: 2.601 Correct answer, well done. Marks for this submission: 0:22/0.22. C and C3 are now connected in parallel and the voltage versus time graph recorded three times as they charge. The graphs are presented below. Use these to calculate the experimental value for C2,3, the capacitance of C2 and C3 in parallel. Graph data Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Pot=mt + b Pot=mt + b Pot=mt + b m (Slope): 1.345 V/S m (Slope): 1.343 V/S m (Slope): 1.344 V/S b (Y-intercept): -3.754 v b (Y-intercept): -4.816V b (Y-intercept): -4.386 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.007736 V RMSE: 0.007888 V RMSE: 0.006530 V C2,3 A series circuit Use the values you found above to predict the capacitance of C and Cy connected in series with an uncertainty. C12 AF C and C are now connected in series and the voltage versus time graph recorded three times as they charge. The graphs are presented below. Use these to calculate the experimental value for C1,2, the capacitance of C and Ca in series. Graph data Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Potemt + b Pot= mt + b Pot= mt + b m (Slope): 2.901 V/S m (Slope): 2.906 V/S m (Slope): 2.907 V/S b (Y-intercept): -5.025 V b (Y-intercept): -4,939 v b (Y-intercept): -4.471 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.009597 v RMSE: 0.008032 V RMSE: 0.007516 V AF C1,2 - Note: You will be asked to compare your prediction and measurement in the next question. You may want to jump to that now and then come back here. A combination circuit Use the values you found for for C1, C2 and C3 above to predict the capacitance if C3 is connected in parallel with C and C in series. C1,2,3 MF Cz is now connected in parallel with C and C2 in series and the voltage versus time graph recorded three times as they charge. The graphs are presented below. Use these to calculate the experimental value for C1,2,3- Graph data Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Pot=mt + b Pot= mt + b Pot=mt + b m (Slope): 1.720 V/S m (Slope): 1.724 V/S m (Slope): 1.725 V/S b (Y-intercept): -4.525 V b (Y-intercept): -4,434 V b (Y-intercept): -3.176 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.006979 V RMSE: 0.005919 V RMSE: 0.006927 V C 1,2,3 Throughout this experiment the current is measured to be I = 2.667 mA. After being discharged capacitor 1 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 1. Graph data Linear fit for Linear fit for Linear fit for Latest|Potential Latest|Potential Latest|Potential Pote mt + b Pot= mt + b Pot=mt + b m (Slope): 0.9089 V/S m (Slope): 0.9100 V/S m (Slope): 0.9100 V/S b (Y-intercept): -3.243 v b (Y-intercept): -2.143 V b (Y-intercept): -1.901 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.007985 V RMSE: 0.008305 V RMSE: 0.008095 V C1 = 2931 +1.77 Your last answer was interpreted as follows: 2931 Your last answer was interpreted as follows: 1.77 Correct answer, well done. Marks for this submission: 0.22/0.22. Correct answer, well done. Marks for this submission: 0.22/0.22. Accounting for previous tries, this gives 0.15/0.22. After being discharged capacitor 2 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 2. Graph data: Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Potemt + b Pot=mt + b Pot=mt + b m (Slope): 1.973 V/S m (Slope): 1.976 V/S m (Slope): 1.977 V/S b (Y-intercept): -3.684 V b(Y-intercept): -3.330 v b (Y-intercept): -3.051 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.007986 V RMSE: 0.008103 v RMSE: 0.007582 v UF C2 = 1350.15 + 1.367 Your last answer was interpreted as follows: 1350.15 Your last answer was interpreted as follows: 1.367 Correct answer, well done. Marks for this submission: 0.22/022. Correct answer, well done. Marks for this submission: 0.22/0.22. After being discharged capacitor 3 is charged three times. The voltage versus time graphs are shown below. Use these to calculate the capacitance of capacitor 3. Graph data Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Pot=mt + b Pot=mt + b Pot=mt + b m (Slope): 4.278 V/s m (Slope): 4.294 V/s m (Slope): 4.295 V/S b(Y-intercept): -9.054 V b (Y-intercept): -6.868 V b (Y-intercept): -8.772 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.01681 V RMSE: 0.005470 V RMSE: 0.007557 v C3 = 621.83 + 1.234 F Your last answer was interpreted as follows: 621.83 Your last answer was interpreted as follows: 1.234 Correct answer, well done. Marks for this submission: 0.22/0.22. Correct answer, well done. Marks for this submission: 0.22/0.22. A parallel circuit Use the values you calculated above to predict the capacitance of C and Cs connected in parallel with an uncertainty. C2,3 AF 1988.81 2.601 Your last answer was interpreted as follows: 1988.81 Your last answer was interpreted as follows: 2.601 Correct answer, well done. Marks for this submission: 0:22/0.22. C and C3 are now connected in parallel and the voltage versus time graph recorded three times as they charge. The graphs are presented below. Use these to calculate the experimental value for C2,3, the capacitance of C2 and C3 in parallel. Graph data Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Pot=mt + b Pot=mt + b Pot=mt + b m (Slope): 1.345 V/S m (Slope): 1.343 V/S m (Slope): 1.344 V/S b (Y-intercept): -3.754 v b (Y-intercept): -4.816V b (Y-intercept): -4.386 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.007736 V RMSE: 0.007888 V RMSE: 0.006530 V C2,3 A series circuit Use the values you found above to predict the capacitance of C and Cy connected in series with an uncertainty. C12 AF C and C are now connected in series and the voltage versus time graph recorded three times as they charge. The graphs are presented below. Use these to calculate the experimental value for C1,2, the capacitance of C and Ca in series. Graph data Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Potemt + b Pot= mt + b Pot= mt + b m (Slope): 2.901 V/S m (Slope): 2.906 V/S m (Slope): 2.907 V/S b (Y-intercept): -5.025 V b (Y-intercept): -4,939 v b (Y-intercept): -4.471 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.009597 v RMSE: 0.008032 V RMSE: 0.007516 V AF C1,2 - Note: You will be asked to compare your prediction and measurement in the next question. You may want to jump to that now and then come back here. A combination circuit Use the values you found for for C1, C2 and C3 above to predict the capacitance if C3 is connected in parallel with C and C in series. C1,2,3 MF Cz is now connected in parallel with C and C2 in series and the voltage versus time graph recorded three times as they charge. The graphs are presented below. Use these to calculate the experimental value for C1,2,3- Graph data Linear fit for Latest|Potential Linear fit for Latest|Potential Linear fit for Latest|Potential Pot=mt + b Pot= mt + b Pot=mt + b m (Slope): 1.720 V/S m (Slope): 1.724 V/S m (Slope): 1.725 V/S b (Y-intercept): -4.525 V b (Y-intercept): -4,434 V b (Y-intercept): -3.176 V Correlation: 1.000 Correlation: 1.000 Correlation: 1.000 RMSE: 0.006979 V RMSE: 0.005919 V RMSE: 0.006927 V C 1,2,3