Hey, if anyone could offer some assistance with this, it would be great. Thanks!

Morse Code: A dash is transmitted as a pulse which is three times as long as a dot. In between the dots and dashes for a letter there was a pause of the length of a dot. After any symbol there was a pause the length of three dots. After the last symbol of a word there was a further pause the length of four dots (so between the last pulse of a word and the first pulse of the next word there would be a pause of the length of 7 dots). In binary we have 0 for a pause and a 1 for a transmission. So the letter A would be 10111000. Think of Morse Code as a Prefix Code where every message ends with a blank and the blank is encoded as 0000.

(a) Draw the tree corresponding to the Morse prefix code

MORSE:

Consider the frequency table for the English language given below and assume that the average word length is 19 letters.

(b) Compute the frequency table for the alphabet consisting of the union of the English language and the blank under this assumption.

FREQUENCY TABLE:

STANDARD LETTER FREQUENCY .0761 .0154 0311 0395 .1262 0234 0195 0551 0734 .0015 .0065 0411 0254 0765 .0203 .0010 0615 0650 0933 .0272 0099 0189 0019 .0172 .0009 STANDARD LETTER FREQUENCY .0761 .0154 0311 0395 .1262 0234 0195 0551 0734 .0015 .0065 0411 0254 0765 .0203 .0010 0615 0650 0933 .0272 0099 0189 0019 .0172 .0009