Hey! I'm struggling with somehow parametrizing the ellipse to be cos2t+sin2t=1. Please help me out, thank you so much!

Using a line integral to calculate area - Let C be a curve enclosing region R as described in Green's Theorem. If we 69 aP choose P and Q such that E W = 1 then for the area of region R we have A = ldA = 5150 de + Qdy. R One possibility that results in '33: = l is P(x, y) = %y and Q(x, y) = %x. We then get the following formula for the area 1 A = ydx + xdy. 2 C Use this formula to find the area enclosed by the ellipse i y: _ +EL Hint: parametrize the ellipse using trig. functions: what must x(t) and 370') be in order for the equation of the ellipse to be cos2 I + sin2 I = 1