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Hi can you explain the following to me? I know the answer is x(t)= C1 e^(-4t) , but I'm not sure why. I understand how

Hi can you explain the following to me?

I know the answer is x(t)= C1 e^(-4t) , but I'm not sure why.

I understand how to get x(t) = e^ (-4t+c) but I am stuck from there.

\f2. Find the solution to the initial value problem (differential equation and initial condition) dx dt -4x, 2(0 ) = 1

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