Hi can you please check my physics reflect report based on impulse practical and see if anything needs changes or something i can add for it to be better

This question deals with uncertainties both in measurements and in calculated quantities. A) Describe how you determined the uncertainty in the measurement of the impulse of the force. (3 marks) To determine the uncertainty in the measurement of the impulse of the force, | followed a systematic approach using PASCO Capstone software and data from the force sensor and motion sensor. First, | collected data from both sensors during the experiment. The force sensor provided the force data, while the motion sensor provided the time data, which was crucial for calculating the impulse using the formula: impulse = force x time. Next, | focused on error analysis to determine the uncertainty in the force measurement from the force sensor. To pl'opagate the uncertainty in the force measurement to the impulse calculation, | applied standard error propagation technigues. This allowed me to quantify the uncertainty in the impulse measurement based on the uncertainty in the force measurement. B) Consider your result for quiz question 1, and describe (if you got it right) or correct (if you got it wrong) your uncertainty calculation for the change in momentum. For this part, you should and justify the key steps in your working through the calculation. (5 marks) Step 1: Understand the given expression for change in momentum, which ism X vl m x v2. Q2 - This expression calculates the change in momentum by subtracting the final momentum (m x v2) from the |nitial momentum ( m x v1). Step 2: Recognize that the uncertainty in a product (or quatient) can be found by adding the relative uncertainties of the components involved, then multiplying by the absolute value of the product (or quotient). The formula for the uncertainty of a product AB (where A and B are measured quantities with uncertainties ud and uB, respectively) is given by u(AB) = A () + (5)" Step 3: Apply the formula for uncertainty in a product to each momentum term separately. For the initial momentum m X v1, the uncertainty is um X v1 + m X uv, since uv is the uncertainty in either velocity ( v1 or v2 ) and um is the uncertainty in the mass m. This simplifies to um X v1 + uv X m using the properties of multiplication. Step 4: Similarly, for the final momentum m X v2, the uncertainty is um X v2 + m X uv, which simplifies to um X v2 + uv X m. Step 5: Recognize that when subtracting quantities, the uncertainties add. Therefore, the total uncertainty in the change in momentum (m X v1 m X v2 ) is the sum of the uncertainties in each term. This means you add the uncertainties found in Steps 3 and 4. Step 6: Combine the expressions for the uncertainties in the initial and final momentum to get the total uncertainty in the change in momentum. This gives us um x vl +uvr xm + um x v2 4+ uv X m. Step 7: Simplify the expression from Step 6. Notice that ur X m appears twice, so it can be combined. The simplified expression for the total uncertainty in the change in momentum is umx (vl +v2) + 2 X ur x m. Step 8: The final expression for the uncertainty in the change in momentum, in terms of the given symbols, is um X (vl + v2) + 2 X uv X m. This formula allows you to calculate the uncertainty in the result of m x v1 m X v2 given the uncertainties in mass (um) and velocity (uv). Interpretation and Discussion of Results - 8 marks In part B ot the laboratory you complete a quick ht to impulse vs change In momentum. The quiz you completed then asked you to clarify what intercept and slope you expect if the Impulse momentum holds and asked you if your results supported the impulse Momentum Theorem (questions 2-5). With the benefit of considering your quiz results, discuss or correct your answers to these questions here. Specifically: a) What are the expected results for the intercept and slope of our fit, and why? (3 marks) b) What were your results for the intercept and slope (with uncertainties)? For this part please provide the values you used in the quiz in whatever format they were entered in, and please also provide the \"correctly formatted\" results for the slope and intercept as well. (2 marks) c) Based on the values (as entered in the quiz) do your results for the slope and intercept match the expected values? Justify your answers. (2 mark) d) Based on all of the above do your results support the impulse and momentum theorem? Justify your claim. (1 mark) a) The expected results for the intercept and slope of the fit to impulse vs. change in momentum can be deduced from the impulse-momentum theorem. According to this theorem, the impulse experienced by an object is equal to the change in momentum of that object. Mathematically, this can be expressed as: Impulse = Change in Momentum Impulse = Force X Time Change in Momentum = Mass X Change InVelocity Given that the slope of a line represents the change in y (impulse) per unit change in x (change in momentum), the slope of the fit should be equal to the mass of the cart. The intercept, on the other hand, should be zero, as there should be no impulse when there is no change in momentum. b) It is slightly off this can be due to equipment and human error and other factors. c) Comparing the entered values with the expected results, the slope matches the expected mass of the cart, which is a positive outcome. However, the intercept is slightly off from the expected value of zero. This discrepancy could be due to experimental errors or limitations in the equipment used. d) Despite the slight discrepancy in the intercept, the overall results support the impulse momentum theorem. The close match between the slope and the mass of the cart indicates that the impulse is indeed equal to the change in momentum, validating the fundamental principle of the theorem. Q3 - Synthesizing Knowledge and Critical Thinking - 8 marks In the final part of the laboratory, you explore collisions with the heavy spring and rubber stopper in addition to with the light spring in the earlier parts. Compare and contrast (qualitatively -if you only sketched graphs - or quantitatively - if you took full data on these) the nature of the force vs time graphs and also the velocity results for each case. Specifically: a) If you are doing things qualitatively please provide the sketches of the graphs in question, and if you are doing them more qualitatively please provide any values (with estimated uncertainties). (3 marks) b) For the force vs time graphs/values, compare the maximum force, the duration of the collision, and the impulse that results for each of the three objects. Consider how the two springs compare to one another and how the rubber stopper compares to the springs. (2 marks) c) For the velocity results for the light spring, do the velocity results support the idea that energy is also conserved in the collision? (1 mark) e V) S6. AN () . d) Finally, discuss, or provide an explanation for, the similarities and differences you note. (2 marks) Light Spring Hard Spring 19+ 0.5 18+0.5 0.08 + 0.05 0.05+0.05 0.5004 0.005 0.490+0.005 Rubber Bumper 5810.5 0.025+0.05 0.360+0.005 Maximum Force (N Duration of Collision (s) Impulse (N/s | determined the uncertainty of the maximum force taking half of the interval = 2 (1) = 0.5 and the uncertainty of the duration of collision was also determined in the same way = 2 (0.1) = 0.05. The maximum force exerted by both springs overlaps within a range of 3 uncertainties, indicating a similar maximum force for both. Similarly, the duration of collisions overlaps within 3 uncertainties, suggesting that the time the cart was in contact with each spring was similar. In contrast, the rubber bumper exhibits a higher maximum force due to its lower elasticity, allowing it to absorb more force. The collision duration is also shorter because the bumper does not need to retract before the cart reverses direction. The rubber bumper cannot propel the cart as effectively as the springs due to its lower elasticity, resulting in a smaller impulse. Reflection The maximum force exerted by both springs overlaps within a range of 3 uncertainties, indicating a similar maximum force for both. Similarly, the duration of collisions overlaps within 3 uncertainties, suggesting that the time the cart was in contact with each spring was similar. In contrast, the rubber bumper exhibits a higher maximum force due to its lower elasticity, allowing it to absorb more force. The collision duration is also shorter because the bumper does not need to retract before the cart reverses direction. The rubber bumper cannot propel the cart as effectively as the springs due to its lower elasticity, resulting in a smaller impulse