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Hi. Each screenshot has instructions on what you are to do. You are to only answer the blanks in each one. Some screenshots include more

Hi. Each screenshot has instructions on what you are to do. You are to only answer the blanks in each one. Some screenshots include more than one part, so be sure to answer those as well. As for anything else, please leave a comment below. And, please number your solutions. Thanks.

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Determine the total area under the standard normal curve for parts (a) through (c) below. For each, be sure to draw a standard normal curve and shade the area that is to be found. Click here to view the standard normal distribution table (page 1), Click here to view the standard normal distribution table (page 2 (a) Determine the total area under the standard normal curve to the left of z = - 1 or to the right of z = 1. Draw a standard normal curve and shade the area that is to be found. Choose the correct graph below. O Click here to view graph d. Click here to view graph c. O Click here to view graph a. Click here to view graph b. The total area under the standard normal curve to the left of z= - 1 or to the right of z = 1 is 0.3174 . (Round to four decimal places as needed.) (b) Determine the total area under the standard normal curve to the left of z = - 1.57 or to the right of z = 2.57. Draw a standard normal curve and shade the area that is to be found. Choose the correct graph below. Click here to view graph b. O Click here to view graph a. O Click here to view graph d. Click here to view graph c. The total area under the standard normal curve to the left of z = - 1.57 or to the right of z = 2.57 is 0.0633 . (Round to four decimal places as needed.) (c) Determine the total area under the standard normal curve to the left of z = - 0.49 or to the right of z = 1.73. Draw a standard normal curve and shade the area that is to be found. Choose the correct graph below. X Graph a Click here to view graph d. O Click here to view graph c. Click here to view graph a. Click here to view graph b. The total area under the standard normal curve to the left of z = - 0.49 or to the right of z = 1.73 is. (Round to four decimal places as needed.) -3 -2 -1 2 3 Print Done Help Me Solve This View an Example Get More Help - Clear All Check Answer2 answer all parts. The number of chocolate chips in an \"ounce bag of chocolate chip cookies is approximately normally distributed with a mean of 1252 chips and standard deviation 129 chips (3) What is the probability that a randomly selected beg contains between 1000 and 1400 chocolaw chips, Inclusive? (b) What is the probability that a randomly selected bag contains fewer than 1050 chocolate chips? (1:) What proportion of bags contains more than 1175 chocolate chips? (d) What is the percentile rank of a bag that contains 1475 chocolate chips? (a) The probability that a randomly selected bag contains between 1000 and 1400 chocolate chips. inclusive. is 0.8490 . (Round to (our decimal places as needed.) (h) The probability that a randomly selected hag contains fewer than 1050 chocolate chips is (Round lo tour decimal places as needed) Help Me Solve This View an Example Get More Help A Clear All 3 Complete parts (a) through (d) for the sampling distribution of the sample mean shown in the accompanying graph. Click the icon to view the graph. (a) What is the value of ux? The value of u- is 300. (b) What is the value of or ? The value of o is 40 . (c) If the sample size is n = 9, what is likely true about the shape of the population? - X A. The shape of the population is approximately normal. Sampling Distribution O B. The shape of the population is skewed left O C. The shape of the population is skewed right. O D. The shape of the population cannot be determined. (d) If the sample size is n = 9, what is the standard deviation of the population from which the sample was drawn? The standard deviation of the population from which the sample was drawn is. 260 300 340 The distribution is normal. The locations of the peak and inflection points are shown. Print Done Help Me Solve This View an Example Get More Help - Clear All Check Answer4 what is boxed in red has already been solved. so, solve "(e)." The reading speed of second grade students in a large city is approximately normal, with a mean of 92 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) through (f). (a) What is the probability a randomly selected student in the city will read more than 98 words per minute? The probability is 0.2743 . (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box within your choice. JA. If 100 different students were chosen from this population, we would expect to read exactly 98 words per minute. B. If 100 different students were chosen from this population, we would expect 27 to read more than 98 words per minute. O C. If 100 different students were chosen from this population, we would expect to read less than 98 words per minute. (b) What is the probability that a random sample of 10 second grade students from the city results in a mean reading rate of more than 98 words per minute? The probability is 0.0287 . (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box within your choice. A. If 100 independent samples of n = 10 students were chosen from this population, we would expect 3 sample(s) to have a sample mean reading rate of more than 98 words per minute. O B. If 100 independent samples of n = 10 students were chosen from this population, we would expect sample(s) to have a sample mean reading rate of less than 98 words per minute. O C. If 100 independent samples of n = 10 students were chosen from this population, we would expect sample(s) to have a sample mean reading rate of exactly 98 words per minute (c) What is the probability that a random sample of 20 second grade students from the city results in a mean reading rate of more than 98 words per minute? The probability is 0.0036 . (Round to four decimal places as needed.) Interpret this probability. Select the correct choice below and fill in the answer box within your choice. A. If 100 independent samples of n = 20 students were chosen from this population, we would expect 0 sample(s) to have a sample mean reading rate of more than 98 words per minute. B. If 100 independent samples of n = 20 students were chosen from this population, we would expect sample(s) to have a sample mean reading rate of less than 98 words per minute. O C. If 100 independent samples of n = 20 students were chosen from this population, we would expect sample(s) to have a sample mean reading rate of exactly 98 words per minute. (d) What effect does increasing the sample size have on the probability? Provide an explanation for this result O A. Increasing the sample size decreases the probability because ox increases as n increases. B. Increasing the sample size decreases the probability because o decreases as n increases. O C. Increasing the sample size increases the probability because o increases as n increases. D. Increasing the sample size increases the probability because o- decreases as n increases. (e) A teacher instituted a new reading program at school. After 10 weeks in the program, it was found that the mean reading speed of a random sample of 22 second grade students was 94.3 wpm. What might you conclude based on this result? Select the correct choice below and fill in the answer boxes within your choice. (Type integers or decimals rounded to four decimal places as needed.) O A. A mean reading rate of 94.3 wom is not unusual since the probability of obtaining a result of 94.3 wom or more is . This means that we would expect a mean reading rate of 94.3 or higher from a population whose mean reading rate is 92 in of every 100 random samples of size n = 22 students. The new program is not abundantly more effective than the old program. O B. A mean reading rate of 94.3 wom is unusual since the probability of obtaining a result of 94.3 wpm or more is . This means that we would expect a mean reading rate of 94.3 or higher from a population whose mean reading rate is 92 in of every 100 random samples of size n = 22 students. The new program is abundantly more effective than the old program. Help Me Solve This View an Example Get More Help - Clear All Check Answer5 A simple random sample of size n = 63 is obtained from a population that is skewed left with u = 85 and o = 5. Does the population need to be normally distributed for the sampling distribution of x to be approximately normally distributed? Why? What is the sampling distribution of x? Does the population need to be normally distributed for the sampling distribution of x to be approximately normally distributed? Why? A. Yes. The central limit theorem states that only for underlying populations that are normal is the shape of the sampling distribution of x normal, regardless of the sample size, n. B. No. The central limit theorem states that regardless of the shape of the underlying population, the sampling distribution of x becomes approximately normal as the sample size, n, increases. O C. No. The central limit theorem states that only if the shape of the underlying population is normal or uniform does the sampling distribution of x become approximately normal as the sample size, n, increases. D. Yes. The central limit theorem states that the sampling variability of nonnormal populations will increase as the sample size increases What is the sampling distribution of x? Select the correct choice below and fill in the answer boxes within your choice. Type integers or decimals rounded to three decimal places as needed.) O A. The sampling distribution of x is approximately normal with u = and or = O B. The sampling distribution of x is uniform with u = and ox = O C. The shape of the sampling distribution of x is unknown with u = and of = O D. The sampling distribution of x is skewed left with u = and x = Help Me Solve This View an Example Get More Help - Clear All Check Answer6 solve all parts (b, c, and d). Suppose a simple random sample of size n = 36 is obtained from a population that is skewed right with u = 71 and o = 24. (a) Describe the sampling distribution of x. (b) What is P (x > 78.4) ? c) What is P (x $61.2) ? (d) What is P (66.2

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