Hi -

I can't figure out where I've gone wrong ? - Any help gratefully received !

Many Thanks

A

A particle confined to the xy-plane is in uniform circular motion around the origin. The x- and y-coordinates of the particle vary with time as follows: x(1) = r cos(of) y(() = > sin(@t). where > = 2.14 m and @ = 1.78 -1. What are the x- and y-components of the particle's velocity at a time when of = 1/6 . Give your answers by entering numbers into the empty boxes below. Vx = 1.90 ms-1 Vy = 3.30 ms . Check Classification: paper, pencil and calculator required. References: Unit 3 Section 2. You have the right answer for the y-component, but your answer for the x-component is not correct. The x- and y-components of the velocity are found by differentiating x(() and y(t) with respect to time. dx(t) dy(t) vy(t) = and Vy(t ) = it Take care when you carry out the differentiations. If a and b are constants, we have: a[a sin( bt)] = ab cost( bt) and a[a cos(bt)] = -ab sin(bt)