Hi I need help on what is the answers in my activity, I'm having a hard time to understand it, I hope that you can help me. Below is the questions and its references

Questions

Example Defective bulbs. Mr. Sy asserts that fewer than 5% of the bulbs that he sells are defective. Suppose 300 bulbs are randomly selected, each are tested and 10 defective bulbs are found. Does this provide sufficient evidence for Mr. Sy to conclude that the fraction of defective bulbs is less than 0.05? Use a = 0.01. INDI SEM 2019-2020 | COL# | ELAMZA BAUTISTA Solution 1. Formulate hypothesis Ho: p = 0.05 Ha: p 30, use the z - test for proportions. This becomes a one - tailed test since the problem suggests a fewer than value. 4. State decision rule Reject Ho if p-value 0.01.Formula To get " ". just divide the total population by the number of items you are interested in i. As a formula. it's written as: p=x where: A $6! 20 Y x is the number of items 1you're interested in "Nu...- n is the total number of items in the population A Sample Proportion, p, is calculated in the same way, except you use data from a sample. Example: In a survey of 3121 people: 412 are under-vaccinated. What is the proportion of under-vaccinated people in the local population? Answer: You don't know population data for the local area: so use the sample data: =xfn 41233121 = {1132 Test of Statistical Hypothesis ( Ho: P = P I,) 4. State the decision rule Reject Ho if Z -1.645. 5. Compute test values P-Po Z = 0.136-0.211 = -10.93 PO(1-PO) 0,211(1-0,211) 3536 6. Make a decision Reject Ho because - 10.93 Ztab = Zazz. (two-tailed test) Otherwise, fail to reject Ho. Ha: p > po Reject Ho if Zc > Ztab = Za. (one-tailed test) Otherwise, fail to reject Ho. Ha: p 30. use the z - test for proportions. This becomes a one - tailed test since the problem suggests a fewer than value. iii-Pu P 1P 3: Engagement Answer the following problem. Show your solutions. 1. Newborn babies are more likely to be boys than girls. A random sample found 13,173 boys were born among 25,468 newborn children. The sample proportion of boys was 0.5172. Is this sample evidence that the birth of boys is more common than the birth of girls in the entire population at 5% significance level? 2. A soft drink maker claims that a majority of adults prefer its leading beverage over that of its main competitor's. To test this claim 500 randomly selected people were given the two beverages in random order to taste. Among them, 270 preferred the soft drink maker's brand, 211 preferred the competitor's brand, and 19 could not make up their minds. Determine whether there is sufficient evidence, at the 5% level of significance, to support the soft drink maker's claim against the default that the population is evenly split in its preference