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Hi, I need help with my calculus assignment A ball is dropped from a 10 meter height, bounces back to 75% of its original height,

Hi, I need help with my calculus assignment

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A ball is dropped from a 10 meter height, bounces back to 75% of its original height, and then bounces again to 75% of that height. How much total vertical distance D does the ball travel between being dropped and the third time it touches the ground? A student has given a nal answer of D = 0.25 111/5. How can you tell, just from the student's answer, that the answer is not correct? (Choose ALL correct answers.) D The answer should be a whole number, not a decimal. CI The sign of the answer should be positive, not negative. [I The answer is too small in magnitude, it should be much larger. CI The answer is too large in magnitude, it should be much smaller. D The units in the answer are incorrect. is the graph of the function 9GB) = Hint: Ask what happens to the vertex of the graph. (1 point) The altitude of a right triangle is 6 cm. Let h be the length of the hypotenuse and let p be the perimeter of the triangle. Express h as a function of p. h ( p) =FFODIemI A ball is dropped from a 10 meter height, bounces back to 75% of its original height, and then bounces again to 75% of that height. How much total vertical distance D does the ball travel between being dropped and the third time it touches the ground? A student gives the following reasoning to nd an approximation: Lower bound: The ball travels 10 meters before the rst bounce, so lOgD. Upper bound: Since the ball bounces twice, and each bounce height is less than 10m, we know that D g 10 + 10 + 10 2 30m. So the total vertical distance traveled is between 10m and 30m. Is this a valid approximation? 0 Yes 0 No, the lower bound reasoning is incorrect (but the upper bound reasoning is correct). 0 No, the upper bound reasoning is incorrect (but the lower bound reasoning is correct). 0 No, both the upper bound reasoning and lower bound reasoning are incorrect. The following graph represents the number of new Covid-19 cases each day in Canada from March 2020 to September 2021. 5,000 8 Sept 2021 New cases: 798 4,000 7-day avg: 723 3,000 2,000 1,000 O May 28 Aug. 14 Oct. 31 Jan. 17 Apr. 5 Jun. 22 Sep. 8 . New cases - 7-day averageChoose all of the following Statements about this graph that are correct. [I The total number of cases from March 2020 to September 2021 was less than 5000. [I There were approximately the same number of new cases on May 28, 2020 and Apr. 5, 2021. [I No day had more than 5000 new cases. [I Adding up all the new cases each day gives the total number of cases. [I If we nd the average number of new cases each day, and multiply this average by the number of days, then we will get the total number of cases. [I Each day in 2021 had a larger number of new cases than each of the days in 2020. [I There were fewer new cases in the month of October 2020, than in the month of May 2021. Find the distance between A and B as indicated on the following picture. Suppose a student writes the following solution. Is it correct? Line 1: The equation of the circle is 3:2 l y2 = 9 Line 2: Isolating 3; gives y = x/ 9 3:3 Line 3: From the picture, the point A is at a: = 2, so its y value is 1/9 (2) = 5 Line 4: From the picture, the point B is at a? = 1, so its 3; value is sh(was Line 5: The distance formula is \"(2:1 $2)2 + (91 y2)2 Line 6: Putting A and B into the distance formula gives \\/(2 1)2 + (v5 92 Line 7: This distance is approximately 3.0579 a} Is the above solution correct? If not, in which line is the rst error? (If there is more than one error, select the line where the FIRST error occurs.) [ Select] v b) What is the correct final answer to the problem (approximated to 4 decimal places)? [ Select ] VProblem: Find the distance between A and B as indicated on the following picture. Question: Which of the following techniques/strategies/theorems could be used to solve this problem? (Choose ALL correct answers.) [I The distance formula between A and B [I Use the distance formula twice (once from A to the origin, and once from the origin to B, then add your answers) [I Add the perpendicular distances from A to the x-axis, then along the x-axis, then from the x-axis to B. [I Draw a right angle triangle where the line segment AB is the hypoteneuse, then use Pythagorean theorem 3'2 + b"2 = c"2

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