Here is the given information.
l1 = 0.88 m
l2 = 0.22 m
l3 = 0.6 m
l4 = 0.7 m
l5 = 0.88 m
H = 0.055 m
lAC = 0.36 m
B (beta) =11 degree
Theeta 1 = 9 degree
n2 =485 rpm
Theeta 2 =60 degree

For the six-bar linkage mechanism shown below, determine: 1, = OE = 1 = OA = 1, = AB = 1 = BE = 1, = CD = B %3D @, = 0, a, =0% 0, = 60 %3D AC = 4E %3D is %3D 0, = 9. 1. All possible positions of links and joints by graphical position analysis. Draw to scale all positions of joints for 16 subsequent positions of link 2 and determine the limits of motion where appropriate. Identify and outline the paths of each moving joint. 2. Linear and angular velocities by graphical velocity analysis for the given position 0, = 60 of the mechanism, as shown above. Draw to scale the velocity vector diagram encompassing all linear velocities to scale, and present the results in a tabular form. 3. Linear and angular accelerations by graphical acceleration analysis for the given position 0, = 60 of the mechanism, as shown above. Draw to scale the acceleration vector diagram encompassing all linear accelerations to scale, and present the results in a tabular form. 4. All instantaneous centres of velocity for the given mechanism using Kennedy's rule, and velocities of joints A, B, C and D using the identified instantaneous centres. Draw all instantaneous centres and velocities to scale on a separate diagram of the mechanism. 5. Analytic solutions for positions, velocities and accelerations by vector loop equations and complex number notation, and present the results in a tabular form. Compare these results with those obtained using the graphical approach. You should have good correlation.