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Hi I'm taking a numerical analysis course and we are using C/ C++ syntax program in the course. I'm a little confused on how to

Hi I'm taking a numerical analysis course and we are using C/ C++ syntax program in the course. I'm a little confused on how to fill in this code for interval bisection to get it to work. Can someone help me out? image text in transcribed
image text in transcribed
The interval bisection method works iff the function is continuous and you can establish an initial left & right guess, such that: f(left) and f(right) have different signs (i.e.: one is positive and the other negative) COMPILE THIS CODE BY RUNNING: gcc interval_bisection04_lab.c-Im The -Im links with the math library #include #include #include double f1 (double x) { double yi y = x*x-2; return y; double f2 (double x) // three roots, Il -3 - sqrt(3) = -4.732050, 11 -3 + sqrt(3) = -1.267949, { double y; y = x*x*x - 30*x - 36; return y; } // f points at a function with one double input and a double output int interval_bisection(double (*f)(double x), double left, double right, double epsilon, int maxreps, double results[2]) // return 0 failure, else 'numreps' (>= 1) // 'maxreps' is the maximum iterations through the loop { // example of a valid function call to f: || double fl; // fl = f(left) ; // The algorithm should continue until 'maxreps' iterations have been // performed or the width of the interval is within 'epsilon' Il your code goes here! }

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