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Hi! Just one problem to solve, number 5. I attached the question and my previous answer to the question that was wrong, they are the

Hi! Just one problem to solve, number 5. I attached the question and my previous answer to the question that was wrong, they are the same problems exactly. My teacher said I did it wrong and that the equation was random. Can you please help? Thank you! Please explain your answer and how you got it :).

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5. A certain radioactive isotope has a halflife of 11 days. If one is to make a table showing the halflife decay ofa sample of this isotope from 32 grams to 1 gram; list the time (in days, starting with t = U} in the first column and the mass remaining (In grams) in the second column, which type of sequence is used in the first column and which type ofsequence Is used in the second column? (2 points) e i U FontFamuy vmv a. .o FvE v55 we) ca y El II r! E X 5. A certain radioactive isotope has a half-life of 11 days. If one is to make a table showing the half-life decay of a sample of this isotope from 32 grams to 1 gram; list the time (in days, starting with t = 0) in the first column and the mass remaining (in grams) in the second column, which type of sequence is used in the first column and which type of sequence is used in the second column? (2 points) First, when you choose to record measurements every 11 days then the table looks like this: Days Mass 0 32 11 16 22 8 33 4 44 2 55 1 Next, to find the remaining mass when the days are not 11, then you have to use the formula which is end amount=beginning amount/2^(time spent/half the life). For this problem, plug in the numbers: 32 2 = 30.045789 grams. So the ending amount is 30.05 rounded. So, for the first column, it is an arithmetic sequence. For the second column, it is a geometric sequence

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