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Ho = 4n x 10 -7 .m a = radius of Helmholtz coils = 15.0 cm qe =-1.60 x 109 C N = number of

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Ho = 4n x 10 -7 .m a = radius of Helmholtz coils = 15.0 cm qe =-1.60 x 109 C N = number of windings in Helmholtz coils = 130 1. Looking at the Helmholtz coil apparatus from the front, the electron beam was directed to the right and then it curled into a counterclockwise circular path. The magnetic field created by the Helmholtz coils was therefore in what direction? (2 points) (Your choices are UP/DOWN/LEFT/RIGHT/TOWARD YOU/AWAY FROM YOU) 2. From your front-view perspective, the conventional current in the Helmholtz Coil is going what way? (2 points) (Your choices are CLOCKWISE or COUNTERCLOCKWISE)3. Let's suppose the figure to the right shows the flat, green, circular path of the electron beam, superimposed over the mirrored measuring scale where the increments are 1.0 cm. For the following questions. assume you're using the accepted values L, L] ] II for charge and mass of the electron (shown above). but DO NOT assume the accelerating voltage or Helmholtz coil current is necessarily within the range you were limited to in lab. SHOW ALL WORK!!(3 points each) If the current through the Helmholtz coil was 1.85 Amps: a) What would the magnitude of the Helmholtz coil's magnetic field be ? Use equation #3 from the lab b) What was the (magnitude of) the electrons' velocity as they traveled in the flat. circular path? Use the same process you used to derive equation #1 from the lab handout but to solve for V not e/m ) What (magnitude of) accelerating voltage was necessary to cause this path? Use the same process for equation #2 from the lab but this time you already have the velocity 4. What is the period for the electron traveling in the circular path as described in the previous question? You may assume you can use the constant velocity equation for circular motion. (4 points) SHOW ALL WORK

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