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Home ;, Math 261 Cell: I Summer 20 Assessment 2.4 Score: SE12 7312 answered Progress saved Done lg 15' 0 Question 3 v 8 m1

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Home ;, Math 261 Cell: I Summer 20 Assessment 2.4 Score: SE12 7312 answered Progress saved Done lg 15' 0 Question 3 v 8 m1 pt '0 5 G) Details Use the chain rule to find the derivative of He) =4\\/' 52:7 + 72:1\" Iype your answer without fractional or negative exponents. Use sqrt'x) for . m) =| Question Help: E] Video Home > Math 261 Calc | Summer 2023 > Assessment 2.5 Progress saved Done Score: 10/16 10/16 answered . Question 15 0/1 pt 05 2 2 0 Details Let x(t) = t - sin(t) CYCLOID and y(t) = 1 - cos(t) At t = 1, 0.54 r(1) = y(1) = dx dt 1= dy dx - It=1 = tangent slope speed (1) = Question Help: Video Submit QuestionHome > Math 261 Calc | Summer 2023 > Assessment 2.5 Progress saved Done a 15' Score: 10H 10.-"16 answered 0 Question 16 v E 0J1 pt '0 5 G 2 G) Details cosh] F|.|.|PRF d . _y t 4 = tangent slope =| dz: speed[4) 2| | Question Help: E] Video Home > Math 261 Calc | Summer 2023 > Assessment 2.4 Score: 8/12 7/12 answered Progress saved Done & VOCO . Question 1 0/1 pt 95 2 0 Details Find the following using the table below. T 1 2 3 4 f(x) 2 4 3 1 f'(x) 1 2 4 3 3 2 4 3 2 4 if h(x) = f(g(x)) then h'(1) = Question Help: Video Submit QuestionCourse | Gradebook Home > Math 261 Calc | Summer 2023 > Assessment 2.4 Progress saved Done & VO CO Score: 8/12 7/12 answered . Question 7 Math 261 Calc | Summer 2023 > Assessment 2.4 Progress saved Done VO -. Score: 8/12 7/12 answered . Question 8 0/1 pt 9 5 2 0 Details Let F(x) = f(f(x)) and G(x) = (F(2) )2 . You also know that f(8) = 12, f(12) = 3, f'(12) = 9, f'(8) = 12 Find F(8) and G'(8) Question Help: Video Submit QuestionCourse Gradebook Home > Math 261 Calc | Summer 2023 > Assessment 2.4 Progress saved Done & VOCO Score: 8/12 7/12 answered . Question 12 0.5/1 pt 05 1 0 Details Let h(x) = tan(2x + 6). Then h'(5) is and h"(5) is Question Help: Video Submit QuestionHome > Math 261 Calc I Summer 2023 > Assessment 2.5 Progress saved Done Score: 10/16 10/16 answered Question 11 a 0J1 pt '0 5 3 2 G) Details Let 2.1:): t3 4:2 + t and y(t) = t2 3t + 3 Att=0, of g it D = tangent slope = C] mm = S Question Help: E] Video Submit Question Home > Math 261 Calc | Summer 2023 > Assessment 2.5 Progress saved Done Score: 10/16 10/16 answered . Question 13 E on pt '0 5 G 2 G) Details Let mm = t3 41:2 + 3% and y(t) = t2 + 1 At t = 2, -.. % t 2 = tangent slope = C] mm = S Question Help: [E] Video

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