Homework: 12.5 Homework * Question 9, 12.5.21 HW Score: 45.45%, 10 of 22 points Q Points: 0 of 1 Find the percent of its under a normal curve between the mean and - 1 14 standard deviations from the moon (Note that positive ind cuts above the moon, while negative indicates boker the moan ) Lick herto see pare Lol the table for meis under the standard normal curve. The phocentage of arom under a formal curve between the mean and - 1, 14 siandand deviations sIs (Band to the moved wet a needed ) Help me solve this Get more help = Clear ametween the mean and - 1.14 standard deviations is | %. Standard Normal Curve Areas (page 1) The column under A gives the proportion Because the curve is symmetric of the area under the entire curve that is about 0, the area between z = 0 between z = 0 and a positive value of z. and a negative value of z can be found by using the corresponding positive value of z. 0 Z A A A A A A 0.00 0.000 0.30 0.118 0.60 0.226 0.90 0.316 1.20 0.385 1.50 0.433 0.01 0.004 0.31 0.122 0.61 0.229 0.91 0.319 1.21 0.387 1.51 0.434 0 02 0.008 0.32 0.126 0.62 0.232 0.92 0.321 1.22 0.389 1.52 0.436 0.03 0.012 0.33 0.129 0.63 0.236 0.93 0.324 1.23 0.391 1 53 0.437 0.04 0.016 0.34 0.133 0.64 0.239 0.94 0.326 1.24 0.393 1.54 0.438 0.05 0 020 0.35 0.137 0.65 0.242 0.95 0.329 1.25 0.394 1.55 0.439 0.06 0.024 0 36 0.141 0.66 0.245 0.96 0.331 1.26 0.396 1.56 0.441 0.07 0.028 0.37 0.144 0.67 0.249 0.97 0.334 1.27 0.398 1.57 0.442 0.08 0,032 0.38 0.148 0.68 0.252 0 98 0.336 1.28 0.400 1.58 0 443 0.09 0.036 0.39 0.152 0.69 0 255 0.99 0.339 1.29 0.401 1.59 0.444 0.10 0.040 0.40 0.155 0.70 0.258 1.00 0.341 1.30 0.403 1.60 0.445 0.11 0.044 041 0.159 0.71 0.261 1.01 0.344 1.31 0.405 1.61 0.446 0.12 0.048 0.42 0.163 0.72 0.264 1.02 0.346 132 0.407 1/62 0.447 an example G 0.13 0 052 0.43 0.166 0.73 0 267 1.03 0.348 1.33 0.408 1.63 0448 0.14 0.056 0.44 0.170 0.74 0.270 1 04 0.351 1.34 0.410 1.64 0.449 0.15 0.060 0.45 0.174 0.75 0.273 1 05 0 353 1.35 0.411 1.65 0.451 0.16 0.064 0.46 0.177 0.76 0.276 1.06 0.355 1.36 0413 1 66 0.452 Print Done\feen the mean and - 1.14 standard deviations is |%% X Standard Normal Curve Areas (page 2) The column under A gives the proportion Because the curve is symmetric of the area under the entire curve that is about 0, the area between 2= 0 between z = 0 and a positive value of z and a negative value of z can be found by using the corresponding positive value of z. A A Z A A A Z A 1.80 0.464 2.10 0.482 2.40 0.492 2.70 0.497 3.00 0.499 3.30 0.500 1.81 0.465 2.11 0.483 2.41 0.492 271 0.497 3.01 0.499 3.31 0.500 1 82 0 466 2.12 0.483 2.42 0.492 2.72 0.497 3.02 0.499 3.32 0.500 1.83 0.466 2.13 0.483 2.43 0.492 2.73 0.497 3.03 0.499 3.33 0.500 1.84 0.467 2.14 0.484 2.44 0.493 2.74 0.497 3.04 0.499 3.34 0.500 1.85 0.468 2.15 0.484 2.45 0.493 2.75 0.497 3.05 0.499 3.35 0.500 1.86 0.469 2.16 0.485 246 0.493 2.76 0.497 3.06 0.499 3.36 0.500 1.87 0.469 2.17 0.485 2.47 0.493 2.77 0.497 3.07 0.499 3.37 0 500 1.88 0.470 2.18 0 485 2 48 0.493 2.78 0.497 3.08 0.499 3.38 0.500 1.89 0.471 2.19 0.486 2.49 0.494 279 0.497 3.09 0.499 3.39 0.500 1.90 0.471 2 20 0.486 2.50 0.494 2.80 0.497 3.10 0.499 3.40 0.500 1.91 0.472 2.21 0.486 2.51 0.494 2.81 0.498 3 11 0.499 3.41 0.500 1.92 0.473 2 22 0.487 2.52 0.494 2.82 0.498 3.12 0.499 3.42 0.500 example G 1.93 0.473 2.23 0.487 2.53 0.494 2 83 0.498 3.13 0.499 3.43 0.500 1.94 0.474 2.24 0.487 2.54 0.494 2.84 0.498 3.14 0499 3.44 0.500 1.95 0.474 2 25 0.488 2 55 0.495 2.85 0.498 3.15 0.499 3.45 0.500 1.96 0.475 2.26 0.488 2 56 0.495 2.86 0.498 3.16 0.499 3.46 0.500 Print Done O Dtween the mean and - 1.14 standard deviations is |%. Standard Normal Curve Areas (page 2) 1.87 0.469 2.17 0.485 2.47 0.493 2.77 0.497 3.07 0.499 3.37 0.500 1.88 0.470 2.18 0.485 2.48 0.493 2.78 0.497 3.08 0.499 3.38 0.500 1.89 0.471 2.19 0.485 2.49 0.494 2.79 0.497 3.09 0.499 3.39 0.500 1.90 0.471 2.20 0.486 2.50 0.494 2.80 0.497 3.10 0.499 3.40 0.500 1.91 0.472 2.21 0.486 2.51 0.494 2.81 0.498 3.11 0.499 3.41 0.500 1.92 0.473 2 22 0.487 2 52 0.494 2.82 0.498 3.12 0.499 3.42 0.500 1.93 0.473 2 23 0.487 2.53 0.494 2.83 0.498 3.13 0.499 3.43 0.500 1.94 0.474 2 24 0.487 2.54 0.494 2.84 0.498 3.14 0.499 3.44 0.500 1.95 0.474 2.25 0.488 2.55 0.495 2 85 0.498 3.15 0.499 3.45 0.500 1.96 0.475 2.26 0.488 2.56 0.495 2 86 0.498 3.16 0.499 3.46 0.500 1.97 0.476 2.27 0.48B 2.57 0.495 2.87 0.498 3.17 0.499 3.47 0.500 1.98 0.476 2 28 0.489 2 58 0.495 2.88 0.498 3.18 0.499 3.48 0.500 1.99 0.477 2.29 0.489 2.59 0.495 2.89 0.498 3.19 0.499 3.49 0.500 2.00 0.477 2.30 0.489 2.60 0.495 2.90 0.498 3.20 0.499 3.50 0.500 2.01 0.478 2.31 0.490 2.61 0.495 291 0.498 3.21 0.499 3.51 0.500 2.02 0 478 232 0.490 2.62 0.496 2.92 0.498 3.22 0.499 3.52 0.500 2.03 0.479 2.33 0.490 2 63 0.496 2.93 0.498 3.23 0.499 3.53 0.500 2.04 0.479 2.34 0.490 2.64 0.496 2.94 0.498 3.24 0.499 3.54 0.500 2 05 0.480 2.35 0 491 2.65 0.496 2 95 0.498 3.25 0.499 3.55 0.500 G 2.06 0.480 2.36 0.491 2.68 0.496 2.96 0.498 3.26 0.499 3.56 0 500 an example 207 0.481 2.37 0 491 2.67 0.496 2.97 0 499 3.27 0.499 3.57 0.500 2 08 0.481 2.38 0.491 2.68 0.496 2.98 0.499 3 28 0.499 3.58 0.500 209 0.482 2.39 0.492 2.69 0.496 2 99 0.499 3 29 0.499 3.59 0.500 Print Done