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Homework: Ch 11 mm: Two ( Question15.'|1-3-19 W 5: 211.1%, 3-7 0' @ 'l ? points P n1.r2 Sample Procedure 3 3 Q Points:0i3f1 A
Homework: Ch 11 mm: Two ( Question15.'|1-3-19 \"W 5\"\": 211.1%, 3-7 0' @ 'l ? points P n1.r2 Sample Procedure 3 3 Q Points:0i3f1 A random sample of 40 adults with no children under the age of 13 years results in a mean daily,I leisure time of 5.41 hours, with a standard deviation of 2.49 hours. A random sample of 40 adults with children under the age of 18 results in a mean dail'yr leisure time of 4.15 hours, with a standard deviation of 1.76 hours. Consimct and interpret a 95% condence interval for the mean ditTerence in leisure time between adults with no children and adults with children (p1 p2) . Let p1 represent the mean leisure hours of adults with no children under the age of 1B and p2 represent the mean leisure hours of adults with children underthe age of 18. The 95% condence intervalfor [p1 p2) is the range from hours to D hours. (Round to two decimal places as needed.)
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