Homework: Chapter 6 Question 6, 6.2.6 Part 1 of 4 Given a normal distribution with u = 46 and o = 5, complete parts (a) through (d) Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table. a. What is the probability that X > 37? P(X > 37) =(Round to four decimal places as needed.)\f3/822 3:18 PM Print 2 0.90 0.01 0.02 0.03 0.04 0.08 0.08 O.07 0.08 1.09 10 | 0.5000 0.5040 0.5080 0.5120 0.5180 0.5199 0.5239 0.5279 05319| 0.5359 ).1 0 5398 0.5438 0.5478 0.5517 0.5657 0 5696 05636 0.5675 05714 0.5753 12 0.5793 0.5832 0.5871 0.5810 0.5948 05987 0.8026 0.8084. 08103 0.8141 Destina 3 08179 0.6217 0.8255 0.8293 0.8531 0.8368 0.8406 0.6443 06480 0.8517 |0.8654 0.8591 0.8628 0.8684 06700 06736 06772 06808 06844 06879 0.8915 0.6850 0.6885 0.7019 0.7054 0.7088 0.7123 07157 07180 07224 07257 0.7291 07324 07357 07389 0.7422 0.7454 0.7486 0.7518 0.7549 0.7680 0.7612 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 07823 07852 Pages 107881 0.7910 07839 0.7987 07985 0.8023 0.8051 08078 08106 0.8133 19 0.8158 0.8186 0.8212 08238 0.8264 08289 0.8315 08340 08585 08389 .0 08413 0.8438 0.8481 0.8485 0.8508 08531 08654 08577 08599 08621 1.1 0.8643 0.8685 0.8686 0/8708 0.8729 0.8749 0.8770 08790 0.8810 0.8830 1.2 08849 0/8889 0.8888 0.8907 08925 0.8944 0.8962 0.8980 08987 09015 1-3 0.9032 0.9049 0.8086 0.9082 0.9089 0.9115 09131 08147 08162 08177 Copies 1.4 0.8192 0.8207 0.9222 09236 0.9251 0.9285 0.9279 0.8282 09306 09319 0.8332 0.9345 09357 0.9370 0.9382 0.9394 0.9406 0.9418 0.9429 09441 0 8452 0.8483 0.8474 0.9484 0.8495 0.9505 0.9515 0.9525 0.9535 0.9545 0.8554 0.8584 0.8573 0.9582 0.9591 0.9599 0.9608 0.8616 0 9625 0.9633 -8 0 9641 0.9649 0.9658 0.9684 0.9671 0.9678 0.9686 0.9693 0.9689 0.9706 Layout .9 0.9713 09719 09726 0.9732 0.9738 0.9744 0.9750 0.9756 0.9781 09787 2.0 09772 09778 0.9783 0.9788 0.9793 0.9798 0.9803 0.9808 09812 0.9817 1 09821 09826 0.9830 0.9834 0.9838 0.9842 0.9846 0.9850 0.9854 0 9857 0.9881 0.9864 0.9868 0.9871 0.9875 0.9878 0.9881 0.9884 0.9887 0.9890 |0.9893 0.8886 0.9898 0.9801 0.9804 0.9806 0.8909 0.9811| 0.8913 08916 Color 40.8918 0.8920 0.9822 0.9825 0.9927 0.9929 0.9931 0.8932 0.8934 0.8938 6 0.9838 0.9840 0.9841 0.9843 0.9845 0.9946 0.9948 0.9949 0.8951 09952 0.9853 0.9955 0.9858 0.9857 0.9959 0.8980 09981 0 9962 08983 0.8984 27 08985 0.9986 0.9687 08988 0.9989 0.9970 0.9971 0.8972 0.9973 0.8974 18 0.8974 0.9875 0.9878 0.8977 0.9977 0.9978 0.9979 0.9979 0 9980 0.9881 2.9 09831 08982 09882 0.9883 0.9834 09884 0.9985 0.9985 0.9986 0.9986 3.0 0 8987 0.8987 0.9887 0.9838 09838 0.9889 0.9989 0.8989 0.9890 0 9980 MoreHomework: Chapter 6 Question 7, 6.2.7-T HW Score: 0%, 0 of 13 points E Part 1 of 4 O Points: 0 of 1 Save The annual per capita consumption of bottled water was 31.7 gallons. Assume that the per capita consumption of bottled water is approximately normally distributed with a mean of 31.7 and a standard deviation of 10 gallons. a. What is the probability that someone consumed more than 37 gallons of bottled water? b. What is the probability that someone consumed between 25 and 35 gallons of bottled water? c. What is the probability that someone consumed less than 25 gallons of bottled water? d. 99.5% of people consumed less than how many gallons of bottled water? a. The probability that someone consumed more than 37 gallons of bottled water is (Round to four decimal places as needed.) Help me solve this View an example Get more help - Clear all Check