Homework: Hw 10.2 Question 5, 10.2.6 HW Score: 6.36%, 2.1 of 33 points O Points: 0 of 1 Save Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 97.25, y = 94.8, r = 0.834, P-value = 0.000, and y =6.61 + 0.91x, where x represents the IQ score of the younger child. Find the best predicted value of y given that the younger child has an IQ of 105? Use a significance level of 0.05. Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is . (Round to two decimal places as needed.)6 36%, 2.1 of 55 points Homework: \"W 10.2 Question 6. 1 Heights (cm) and weights (kg) are measured [or 100 randomly selected adult males, and range lrom heights o! 131 to 194 cm and weights of 41 to 150 kg. Let the predictor variable x be the rst variable given. The 100 paired measurements yield i= 167.77 cm, r= 81.51 lg, r = 0.111, P-value = 0.272, and ; = - 102 +1.08x. Find the best predicted value at; (weight) given an adult male who is 151 cm tall. Use a 0.10 signicance level. The best predicted value at; [or an adult male who is 151 cm tall is D kg. (Round to two decimal places as needed.) Homework: Hw 10.2 Question 9, 10.2.13 HW Score: 6.36%, 2.1 of 33 points Part 1 of 3 O Points: 0 of 1 Save The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 58 inches. Is the result close to the actual weight of 552 pounds? Use a significance level of 0.05. Chest size 46 57 53 41 40 40 - Critical values of the pearson correlation coefficient r X (inches Weight (pounds) 384 580 542 358 306 320 Click the icon to view the critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Coefficient r n x = 0.05 a = 0.01 NOTE: To test Ho: What is the regression equation? .950 0.990 = 0 against H1: 0.878 0.959 y = +x (Round to one decimal place as needed.) 6 p # 0, reject Ho if 0.811 0.917 0.754 the absolute value 0.875 8 of r is greater than 0.707 0.834 the critical value in 9 0.666 0.798 the table. 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 .661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 .444 0.561 25 0.396 0.505 30 0.361 0.463 35 0.335 0.430 40 0.312 0.402 45 0.294 0.378 50 0.279 0.361 60 .254 0.330 70 0.23 0.305 80 0.220 0.286 90 .207 0.269 100 0.196 0.256 n a = 0.05 x = 0.01Question 10. 10.2 , of 33 points Pal't1 ot3 nd the regression equation, letting the rst variable be the predictor (x) variable. Using the listed lemonlcrash data. where lemon imports are in metric tons and the fatality rates are per 100,000 people. nd the best predicted crash fatality rate [or a year in which there are 500 metric tons 0! lemon imports. Is the prediction worthwhile? Lemon 233 268 364 476 535 :1 Imports Crash Fatallty 15.9157 15.4 15.3 14.6 Rate Find the equation oi the regression line. . y = | + (I )x (Round the yintercept to three decimal places as needed. Round the slope to four decimal places as needed.) Question 11, 10.2.22 = Homework: Hw 10.2 HW Score: 6.36%, 2.1 of 33 points Part 1 of 3 O Points: 0 of 1 Save The data show the bug chirps per minute at different temperatures. Find the regression equation, letting the first variable be the independent (x) variable. Find the best predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per minute. Use a significance level of 0.05. What is wrong with this predicted value? Chirps in 1 min 1112 759 1168 975 938 1126- Temperature (F) 88.9 66.3 90.5 75.7 81.7 87.7 What is the regression equation? y = [+x (Round the x-coefficient to four decimal places as needed. Round the constant to two decimal places as needed.)Question 12, 10.2.23 Homework: Hw 10.2 HW Score: 6.36%, 2.1 of 33 points Save Part 1 of 3 O Points: 0 of 1 Find the regression equation, letting overhead width be the predictor (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 2.2 cm. Can the prediction be correct? What is wrong with predicting the weight in this case? Use a significance level of 0.05. Overhead Width 8.2 7.2 9.9 8.9 7.3 9.1 (cm Weight (kg) 166 154 261 193 149 230 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y =|+x. (Round to one decimal place as needed.)Homework: Hw 10.2 Question 13, 10.2.24 HW Score: 6.36%, 2.1 of 33 points Part 1 of 3 O Points: 0 of 1 Save The data show the number of viewers for television stars with certain salaries. Find the regression equation, letting salary be the independent (x) variable. Find the best predicted number of viewers for a television star with a salary of $3 million. Is the result close to the actual number of viewers, 2.0 million? Use a significance level of 0.05. Salary (millions of $) 9 7 5 2 6 4 9 15 Viewers (millions) 4.1 2.2 1.4 4.4 8.3 8.8 4.9 4.3 Click the icon to view the critical values of the Pearson correlation coefficient r. What is the regression equation? y = [+x (Round to three decimal places as needed.)Homework: Hw 10.2 Question 14, 10.2.27 HW Score: 6.36%, 2.1 of 33 points Part 1 of 3 Save O Points: 0 of 1 Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.4 cm. How does the result compare to the actual circumference of 4.4 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball Diameter 7.5 23.9 4.4 21.7 6.9 4.1 20.5 Circumference 23.6 75.1 13.8 68.2 21.7 12.9 64.4 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y = ]+x. (Round to five decimal places as needed.)Homework: Hw 10.2 Question 14, 10.2.27 HW Score: 6.36%, 2.1 of 33 points Part 1 of 3 O Points: 0 of 1 Sav Find the regression equation, letting the diameter be the predictor (x) variable. Find the best predicted circumference of a marble with a diameter of 1.4 cm. How does the result compare to the actual circumference of 4.4 cm? Use a significance level of 0.05. Baseball Basketball Golf Soccer Tennis Ping-Pong Volleyball X Diameter 7.5 23.9 4.4 21.7 6.9 4.1 20.5 Critical values of the pearson correlation coefficient r Circumference 23.6 75.1 13.8 68.2 21.7 12.9 64.4 Click the icon to view the critical values of the Pearson correlation coefficier a = 0.05 a = 0.01 NOTE: To test Ho: The regression equation is y = |+ x. 0.950 0.990 p = 0 against H1: (Round to five decimal places as needed.) 0.878 0.959 p #0, reject Ho if 0.811 10.917 0.754 the absolute value 0.875 of r is greater than 0.707 0.834 the critical value in 0.666 10.798 the table. 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444 0.561 25 0.396 0.505 30 0.36 0.463 35 0.335 0.430 40 0.312 0.402 45 0.294 0.378 50 0.279 0.361 60 0.254 0.330 70 0.236 0.305 80 0.220 0.286 190 0.207 0.269 100 0.196 0.256 In or = 0.05 a = 0.01Budget ($)in Millions Listed below are paired data consisting of movie budget amounts and the amounts that the movies grossed. Find the regression equation, letting the budget be the predictor (x) variable. Find the best predicted amount that a movie will gross if its budget is $135 million. Use a significance level of a = 0.05. 43 21 112 67 79 50 124 68 11 63 Gross ($ 127 21 15 155 79 in Millions 112 17 110 69 121 108 108 91 60 97 213 43 12 283 46 Click the icon to view the critical values of the Pearson correlation coefficient r. The regression equation is y = ]+ x. Critical values of the pearson correlation coefficient r X Round to one decimal place as needed.) a = 0.05 a = 0.01 NOTE: To test Ho- 0.950 0.990 p =0 against H1: 0.878 0.959 p #0, reject Ho if 0.811 0.917 0.75 0.875 the absolute value of r is greater than 0.707 0.834 the critical value in 0.666 0.798 the table. 10 0.632 0.765 11 0.602 10.735 12 0.57 0.70 13 0.55 0.684 14 0.53 0.661 15 0.514 0.64 16 0.49 0.623 17 0.482 0.606 18 0.468 .590 0.456 10.575 20 0.444 65 0.561 0.39 0.505 0.361 0.46 0.335 0.430 40 0.312 0.402 45 0.294 0.37 ).27 0.361 0.254 0.330 70 0.236 0.305 80 0.220 0.286 90 0.20 0.269 100 0. 196 10.256 a =0.05 a = 0.01Question 1, 10.2.1 =Homework: Hw 10.2 HW Score: 6.36%, 2.1 of 33 points Save Part 1 of 2 O Points: 0 of 1 Different hotels in a certain area are randomly selected, and their ratings and prices were obtained online. Using technology, with x representing the ratings and y representing price, we find that the regression equation has a slope of 125 and a y-intercept of - 354. Complete parts (a) and (b) below. at is the equation of the regression line? Select the correct choice below and fill in the answer boxes to complete your choice. OA. y= + ( ) x OB. y = + ( )x O C. y= + ( )x OD. y = + ( ) x