Homework: Section 1... Question 11, 13.3.18 HW Score: 0%, 0 of 11 points Part 1 of 3 O Points: 0 of 1 Save To illustrate that the length of a smooth space curve does not depend on the parameterization used to compute it, calculate the length of one turn of the helix with the following parameterizations. a. r(t) = (cos 4t)i + (sin 4t)j + 4tk, 0sts - 2 or b. r(t) = cos 1= 27 c. r(t) = (cost)i - (sin t)j - tk, - 2Sts0 Note that the helix shown to the right is just one example of such a helix, and does not exactly correspond to the parametrizations in parts a, b, or c. (1, 0,0) = 0Question 10, 13.3.14 HW Score: 0%, 0 of 11 points = Homework: Section 1... O O Points: 0 of 1 Save Part 1 of 2 Find the arc length parameter along the curve from the point where t= 0 by evaluating the integral s = | |v(t)| dt. Then find the length of the indicated portion of the 0 curve. r(t) = (8 + 4t)i + (9 + 3t)j + (7 - 3t)k, - 1sts0 . . . . . The arc length parameter is s(t) = (Type an exact answer, using radicals as needed.)E Homework: Section 1... Question 9, 13.3.13 HW Score: 0%, 0 of 11 points Part 1 of 2 O Points: 0 of 1 Save + Find the arc length parameter along the curve from the point where t= 0 by evaluating the integral s = | |vidt. Then find the length of the indicated portion of the curve. r(t) = (5e cost) i+ (5e sint)j +5ek, - In4sts0 . . . . . The arc length parameter is s(t) =. (Type an exact answer, using radicals as needed.)= Homework: Section 1... Question 8, 13.3.11 HW Score: 0%, 0 of 11 points