Hooke's Law Pre-lab-online Chart 2: The Second Spring Mission: Find the spring constant of two different springs. Introduction: A spring will respond with a linear restoring force if displaced from equilibrium. We can use grams Kg F (N) Y ( m) this property to find the Spring Constant of two different springs, which is a measure of the "stiffness" of the spring. 200.00 -0.03 The linear relationship is: F = -ky where y is the displacement from equilibrium in meters, and k is the 500.00 -0.07 spring constant in newtons/meter. We are going to try and determine the spring constants of two separate springs. 1000.00 0.13 Procedure: The chart below represents springs being stretched as various weights are attached under the influence of 1500.00 -0.20 gravity. 2000.00 -0.26 1. Convert the masses to kg. Recall there are 1000 grams per kilogram. 2. Then using g= -9.80 m/s| determine the force for each displacement. 2500.00 -0.33 3. Graph F versus x. Use Excel or google sheets. Pass a straight line through your data, and using two widely distanced points, determine the slope of your best fit line. 4. The slopes are your experimentally determined values for the spring constants. Spring constant K2 Chart 1: The First Spring Question: Which spring do you think would be stiffer? Why? grams Kg F (N) Y (m) 100 -0.02 200 -0.03 500 -0.08 1000 0.16 1500 0.25 2000 -0.33 Spring constant K1