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hours per year and the MARR =8% per year. (1hp=0.746kW) a. If electricity costs $X per kilowatt-hour, calculate the annual cost of electrical power for

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hours per year and the MARR =8% per year. (1hp=0.746kW) a. If electricity costs $X per kilowatt-hour, calculate the annual cost of electrical power for each motor b. What cost of electricity ($/kWh) makes the two pumps breakeven (i.e. have the same equivalent annual cost)? Assume repeatability and MVs = $0. c. Choose the graph to illustrate your answer to Part (b). d. Which motor should be selected? Click the icon to view the datatable for the additional information about two alternatives. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 8% per year. a. The annual cost of electrical power for Motor A is $1 The annual cost of electrical power for Motor B is $1 X ). (Round to two decimal places.) X). (Round to two decimal places.) b. The cost of electricity that makes the two pumps breakeven is $0.0106/kWh. (Round to four decimal places.) \begin{tabular}{lcc} \hline & Motor A & Motor B \\ \hline Initial cost & $1,200 & $500 \\ Electrical efficiency & 0.85 & 0.59 \\ Annual maintenance & $560 & $300 \\ Life & 5 years & 12 years \\ \hline \end{tabular} hours per year and the MARR =8% per year. (1hp=0.746kW) a. If electricity costs $X per kilowatt-hour, calculate the annual cost of electrical power for each motor b. What cost of electricity ($/kWh) makes the two pumps breakeven (i.e. have the same equivalent annual cost)? Assume repeatability and MVs = $0. c. Choose the graph to illustrate your answer to Part (b). d. Which motor should be selected? Click the icon to view the datatable for the additional information about two alternatives. Click the icon to view the interest and annuity table for discrete compounding when the MARR is 8% per year. a. The annual cost of electrical power for Motor A is $1 The annual cost of electrical power for Motor B is $1 X ). (Round to two decimal places.) X). (Round to two decimal places.) b. The cost of electricity that makes the two pumps breakeven is $0.0106/kWh. (Round to four decimal places.) \begin{tabular}{lcc} \hline & Motor A & Motor B \\ \hline Initial cost & $1,200 & $500 \\ Electrical efficiency & 0.85 & 0.59 \\ Annual maintenance & $560 & $300 \\ Life & 5 years & 12 years \\ \hline \end{tabular}

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