How do I incorporate these 2 and peer respond: Good evening Class, I will say these discussions get more challenging each week. This week I will say I appreciate Professor allowing each of our peers to be able to feed off of one another allowing us to check our work. With the help of each other and the handy helpers that are provided I can not express how grateful I am we get to use these. I will say this one took me over a good 45 mins to understand this weeks formulas. So you will see below here is what I found for the confidence interval using t-critical value. The formula I utilized is as follows: + or -t*(SD/SQRT(n)) Mean: $48,251 SD: 7324.14526556588 T-Critical Value: =T.INV(0.975,9) = 2.262157163 ME:$16,568.37 My upper is: =48251+2.262157*(23160.98/SQRT(10)) $64,819 My lower is: =48251-2.262157*(23160.98/(10)) $43,012 The population mean car price for the type of cars I selected during week 1 is between $64,819 and $43,012. -------------------------------------------------------------------------------------------------------------------------------------- For confidence intervals for the cars that fall under the mean using z-critical value I used the following formula We will all have the same outcome of 1.96 by =NORM.S.INV(0.975) P + or - z(SQRT(p*q/n) =0.6+1.96*(SQRT(0.6*0.4/10)) Upper= 90.36 =0.6-1.96*(SQRT(0.6*0.4/10)) Lower= 26.64 In your second peer posts, pick another confidence level, i.e. 90%, 99%, 97%, any other confidence level is fine. Have fun and be creative with it and calculate another proportion interval and interpret your results. Compare your results to that of the initial 95%, how much do they differ? How useful can this type of information be when you go to buy a new car, or even a house