How do I solve this entire question? Please show all steps and read question carefully. Nuclear reaction notation is in the "X(a,b)Y" where a= projectile, b= ejectile, X= target, Y= Heavy residual.

4. The figure below shows the largest neutron-induced reaction cross sections on 230 Pu up to En= 20 MeV in a linear-linear plot EXCEPT for the total and fission cross sections. 5 10 15 20 5 4 1 4 3 3 TTTTTTTTT TITT TITT Cross Section (barns) 2 2 2 4 1 5 W 10 15 20 0 Incident Energy (MeV) a. Label the reactions in the table below using nuclear reaction notation (2.5 pts.) Label 1 2 I w 4 5 b. Use this plot to determine the approximate neutron separation energy in 239 Pu and 94P 238Pu. Show your reasoning (2 pts.)?c. Assume that a beam of 101\" 20 MeV neutrons per second are incident on a 1 mm thick 232191.: foil. The density of 232191;. is 19.9 g/cm3 and you may assume that the mole weight of 232191.: is 239 g. How many 231131.: are created per second (2 pts.)? The half-life of 231191;. is 45.64 days. Approximately what is the activity due to the 231m in the foil after 1 gear of irradiation (1 pts.)? ZgiPu eventually decays to 2333i. List all of the particles emitted this decay chain (3 pts.) The yrast rotational band in 233131.: can be populated via the (as, 05') reaction using an a-particle beam of 40 MeV. What is the angle and energy of the scattered a. that would correspond to the excitation of the yrast 4* level at Ex = 146 keV? (2 pts.) CONSTANTS CO. Speed of light 2.99792458 x 108 m/s Charge of electron 1.602189 x 10-19 C Boltzmann constant 1.38066 X 10-23 J/K 8.6174 X 10 -5 eV/K Planck's constant h 6.62618 X 10-34 J . S 4.13570 x 10 -15 e eVS . h= h/2n 1.054589.X 10 34.J 34 . J. 6.58217 x 10-16 eV . s Gravitational constant G 6.6726 X 10-11 N . m2 /kg2 Avogadro's number NA 6.022045 x 1023 mole -1 Universal gas constant K 8.3144 J/mole . K Stefan-Boltzmann constant 5.6703 X 10-8 W/m2 . K4 Rydberg constant 1.0973732 x 10' m-1 Hydrogen ionization energy 13.60580 eV Bohr radius do 5.291771 x 10-11 m Bohr magneton P B 9.27408 X 10-24 J/T 5.78838 X 10-eV/T Nuclear magneton 5.05084 X 10-27 J/T 3.15245 x 10-8 eV/T Fine structure constant 1/137.0360 hc 1239.853 MeV . fm hc 197.329 MeV . fm e 2/4 TIED 1.439976 MeV . fm PARTICLE REST MASSES MeV/c2 Electron 5.485803 X 10-4 0.511003 Proton 1.00727647 938.280 Neutron 1.00866501 939.573 Deuteron 2.01355321 1875.628 Alpha 4.00150618 3727.409 0.1498300 139.5669 0.1448999 134.9745 0.1134292 105.6595 CONVERSION FACTORS 1 e.V = 1.602189 X 10-19 J 1 b = 10-28 m2 1 u = 931.502 MeV/c2 1 Ci = 3.7 x 1010 decays/s = 1.660566 X 10-27 kgShow your work and explain your reasoning clearly. You are allowed one page of notes (both sides). PLEASE WRITE YOUR STUDENT ID ON ALL PAGES! PLEASE PUT THE PROBLEM # ON TOP OF ANY ADDITIONAL SHEETS YOU USE! Group - 1 2 7 9 10 11 12 13 15 16 17 18 Period 2 I He 4 10 Be N O Ne 11 12 14 15 16 18 Na Ma Al 5 Ar 19 20 21 23 24 25 26 27 28 29 30 31 32 33 34 35 36 ca Sc V Cr Mn Fe Co Ni Cu Zn Ga Ge AS Se Kr 38 39 40 43 45 46 48 49 50 TC 52 53 54 Rb Sr Zr Nb Mo To Ru 3h Pd Ag Cd In Sn sb Te Xe 56 12 76 78 79 80 81 32 84 86 CS Ba Hf Ta W Re Os pt Au Ha TI Ri Po At Rn 87 88 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 Ra Rf Db Sq HS Mt DS Rg En Mh Mc LV TS Og Lanthanides 57 58 59 60 62 63 64 65 66 67 68 69 70 71 La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Actinides 89 90 91 93 94 95 96 9 98 99 100 101 102 103 Ac Th Pa Np Pu Am Cm BK Cf ES Fm Md No Lr (E1) = 1.0 x 1014 A2/3 E3 MIC 1(E2) = 7.3 x 107 A4/3E5 Atotal = Ay (1 + a); a = (E3) = 34 A2 EZ Feather's Rule: (E4) = 1.1 x 10-5 A8/3 E9 Energy (MeV) Range (cmz) = 2 1(E5) = 2.4 x 10-12 A10/3 E11 A(M1) = 5.6 X 1013 E3 Bragg-Kleeman Rule: 2(M2) = 3.5 x 107 A2/3 E5 R1 _ P2 VA1 2(M3) = 16 A4/3 EZ R2 P1 VA 2 2(M4) = 4.5 x 10-6 ARE9 2(M5) = 7.4 x 10-13 A8/3611 At = 8 singNote that the slope EMPIRE calculations for n+197Au Example of the of the "rising edge" decreases with 3000 (z.n) (z.Zn) (z,30) types of reaction (z.40) (z.5n) (z,p) increasing (Z.P) (z,t) (z,3np) evaporated neutron 2500 (z,40p) (z, 5np) # due to the range While the slope of of energy 2000 the "falling edge" possibilities in the shows a "flattening Cross Section (mb)/ outgoing neutrons 1500 off" 1000 500 O O 20 30 40 Neutron Energy (MeV) Each successive exit channel has a higher Ethreshold to allow for particle emission (S, or Sp) and K.E