How do they get the answer $-1\mathrm{.}93$ x $10^5$ in this problem An ideal monatomic gas contracts in an isobaric process from $1\mathrm{.}15$ m$3$ to $0\mathrm{.}600$ m$3$ at a constant pressure of $1\mathrm{.}40105$ Pa$.$ If the initial temperature is $405$ K$,$ find the work done on the gas, the change in internal energy, the energy transfer Q$,$ and the final temperature. HINT $($a$)$ the work done on the gas $($in J$)$ J $($b$)$ the change in internal energy $($in J$)$ J $($c$)$ the energy transfer Q $($in J$)$ Incorrect: Your answer is incorrect. seenKey $-1\mathrm{.}93$e$+05$ J $($d$)$ the final temperature $($in K$)$