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How do you calculate the maximum value of the given function? f(x) = ln(x^2-6x+11) The critical number (s) is 3 and I thought that the
How do you calculate the maximum value of the given function?
f(x) = ln(x^2-6x+11)
The critical number (s) is 3 and I thought that the maximum value of the function was zero but the answer was wrong. I even did 0.6931471806 and still the answer was wrong.
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