How is p-value 0.0259, using the tcdf function on a TI-84 calculator? I got my test statistic by using 2-SampTTest function and used the p-value given, but it was incorrect.

You wish to test the following claim (Ha) at a significance level of a = 0.001. Ho=m=2 Harm <.u2 you believe both populations are normally distributed but do not know the standard deviations for either. however also have no reason to variances of two equal use option obtain a sample size with mean m1="89.9" and deviation sd1="16.4" from first population. m2="100.5" second what is test statistic this answer accurate three decimal places. cs p-value tcdf entering degree freedom smaller four is... less than o greater leads decision to... reject null accept fail>