How many grams of oxygen are required per electron equivalent of glucose in wastewater when subjected to aerobic treatment if $f_s^0$ is $0\mathrm{.}4$ Assume that there is sufficient ammonium available for cell synthesis.

Calculate the true yield $($Y$)$ of cell synthesis.

$Y=f_s^0*\frac{Mc}{n_e*8}$

$Mc=$ Molecular weight of cells.

$f_s^0=e^{-}$eq dedicated for biomass synthesis.

$n_e=$ number of electron equivalents per mol of cell.

$8=$ number of grams of $02$ to accept one e$-$ eq from donor.

$Y$ has units of $g$ cells$/$g COD

Units $=g$ cells $\frac{?}{\text{m}\text{o}\text{l}}$ cells

Units $=e^{-}$eq

Units $=e^{-}e\frac{q}{m}ol$ cells

Units $=g$ COD$/$e $e{q}^{-}$