How many liters of NH$3($g$)$ at $738$ oC and $3\mathrm{.}5$ atm are required to react with $2\mathrm{.}00$ mol of O$2($g$)$ in this reaction? Upload a picture of your work$*$

$4$ NH$3($g$)+5$ O$2($g$)-->4$ NO$($g$)+6$ H$2$O$($g$)$