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How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO 3 (= 84.02 g/mol)? HCl( aq )+ NaHCO
How many milliliters of 1.58 M HCl are needed to react completely with 23.2 g of NaHCO3 (= 84.02 g/mol)?
HCl(aq) + NaHCO3(s) ? NaCl(s) + H2O(l) + CO2(g)
| a. | 175 mL | |
| b. | 536 mL | |
| c. | 276 mL | |
| d. | 572 mL | |
| e. | 638 mL |
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Accounting
Authors: Jonathan E. Duchac, James M. Reeve, Carl S. Warren
23rd Edition
978-0324662962
