How many years will it take for an investment of $$4,000$ to double at an annual interest rate of $6\%?$

Question $7$Answer

a$.$

t$=$Ln$($$$4,000$$$8,000)$Ln$(1+0\mathrm{.}06)=11\mathrm{.}8956$ years

b$.$

t$=$Log$($$$8,000$$$4,000)$Log$(1+0\mathrm{.}06)=11\mathrm{.}8956$ years

c$.$

t$=$Ln$($$$8,000$$$4,000)$Ln$(1+0\mathrm{.}06)=12\mathrm{.}4312$ years

d$.$

t$=$Ln$($$$8,000$$$4,000)$Ln$(1+0\mathrm{.}06)=11\mathrm{.}8956$ years