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how to do the 3 force and 4 force graphical method using the below data to find the resultant? Then doing the resultant using the
how to do the 3 force and 4 force graphical method using the below data to find the resultant? Then doing the resultant using the component method. And doing the error analysis for three force and four force.
Component method ifn Fry = 15/ Sinen = Mingsinon" X Fax How to old Vectors . Fox = 1FICOsen = mag cosen Graphical Method A is from the Forcetable. M is the mass on the end of the string. 3 force Example /F,1 = IN Q = 75' IF21 = 2N, 02 = 120 Force Equilibrium Tho IF 1 = 1.SN, &, = 1650 Fal = IN, Or = 1750 RI = ( ) + ( 2fry ) OF= O - - Vector Sum SF = R= Resultant = = -E = - [ = Equilibrant ane Of= tanil 4 3 N Force is a vector, It has Magnatude and direction . I p 180 E= Fi+ Fyj E = F Error Estamate: OF =(Mi- mc) Where L. I are unit vectors Ichoose the scale ( Fill the 19 inthe Xy directions "Graph Paper ! ) 3 Force ? ) Draw Vectors to scale with IF1 = magnetade = mg m=m, +m direction almost hanger outhanger 3) Draw Vector Heed to tail Touch I RH 2 OF > /E1 2 1 R1 - 2OF O. = read from the force table How do we add Vectors? " Compare Fu= E= - P? IEI = Magfromtable. 4 Force No error Analysis. D .6 Not Erase ! m , R + 30 1 =1E12 R- 3AFZOOM + force equilibrium data file 3 force case m1(kg) 0 (degrees) m2(kg) 0 (degrees) 0.1 20 0.2 75 Mass of Equilabrant (kg) ang of Equiibrant degrees 0.27 237 M high(kg) 0.29 M low (kg) = 0.25 4 force case m1(kg) 0 (degrees) m2(kg) 0 (degrees) m3(kg) 0 (degrees) 0.15 20 0.1 80 0.2 110 Mass of Equilabrant (kg) ang of Equiibrant degrees 0.35 255 use the same M high and M lowStep by Step Solution
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