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How to find the last one? Consider the curve with parametric equation a(t) = [213+ 1,252 +3t+2] ,t e R. The equation of the: .

How to find the last one?

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Consider the curve with parametric equation a(t) = [213+ 1,252 +3t+2] ,t e R. The equation of the: . tangent to the curve at the point (1(1) is y = a . normal to the curve at the point (1(1) is y = a. By eliminating the parameter t , we nd that the Cartesian equation of the curve is: 9= :I The curve (in black), tangent (in blue) and normal (in red) are displayed below

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